c++ - プログラマーがメンバーの初期化のためにセマンティクスのコピーと移動のどちらかを選択できるようにする非反復的な方法はありますか?

Question

移動セマンティクスまたはコピー セマンティクスを使用して、クラスの各フィールドを初期化できるようにしたいと考えています。コンストラクターはすべて、次のように、基本的に同じコードを使用して構築します。

LogRecord::LogRecord(const Logger &logger, LogLevel level, const std::wstring &message)
    : level(level), logger_name(logger.GetName()), message(message), sequence_number(LogRecord::record_count++), source_class_name(), source_method_name(), time(std::chrono::system_clock::now()) {
}
LogRecord::LogRecord(const Logger &logger, LogLevel level, std::wstring &&message)
    : level(level), logger_name(logger.GetName()), message(message), sequence_number(LogRecord::record_count++), source_class_name(), source_method_name(), time(std::chrono::system_clock::now()) {
}
LogRecord::LogRecord(const Logger &logger, LogLevel level, const std::wstring &message, const std::wstring &source_class_name, const std::wstring &source_method_name)
    : level(level), logger_name(logger.GetName()), message(message), sequence_number(LogRecord::record_count++), source_class_name(source_class_name), source_method_name(source_method_name), time(std::chrono::system_clock::now()) {
}
LogRecord::LogRecord(const Logger &logger, LogLevel level, std::wstring &&message, const std::wstring &source_class_name, const std::wstring &source_method_name)
    : level(level), logger_name(logger.GetName()), message(message), sequence_number(LogRecord::record_count++), source_class_name(source_class_name), source_method_name(source_method_name), time(std::chrono::system_clock::now()) {
}
LogRecord::LogRecord(const Logger &logger, LogLevel level, const std::wstring &message, std::wstring &&source_class_name, const std::wstring &source_method_name)
    : level(level), logger_name(logger.GetName()), message(message), sequence_number(LogRecord::record_count++), source_class_name(source_class_name), source_method_name(source_method_name), time(std::chrono::system_clock::now()) {
}
LogRecord::LogRecord(const Logger &logger, LogLevel level, std::wstring &&message, std::wstring &&source_class_name, const std::wstring &source_method_name)
    : level(level), logger_name(logger.GetName()), message(message), sequence_number(LogRecord::record_count++), source_class_name(source_class_name), source_method_name(source_method_name), time(std::chrono::system_clock::now()) {
}

等

このように、可能な組み合わせごとにコンストラクターを宣言するよりも、これを行うためのより良い方法はありますか?

class LogRecord {
public:
    LogRecord(const Logger &logger, LogLevel level, const std::wstring &message);
    LogRecord(const Logger &logger, LogLevel level, std::wstring &&message);
    LogRecord(const Logger &logger, LogLevel level, const std::wstring &message, const std::wstring &source_class_name, const std::wstring &source_method_name);
    LogRecord(const Logger &logger, LogLevel level, std::wstring &&message, const std::wstring &source_class_name, const std::wstring &source_method_name);
    LogRecord(const Logger &logger, LogLevel level, const std::wstring &message, std::wstring &&source_class_name, const std::wstring &source_method_name);
    LogRecord(const Logger &logger, LogLevel level, std::wstring &&message, std::wstring &&source_class_name, const std::wstring &source_method_name);
    LogRecord(const Logger &logger, LogLevel level, const std::wstring &message, const std::wstring &source_class_name, std::wstring &&source_method_name);
    LogRecord(const Logger &logger, LogLevel level, std::wstring &&message, const std::wstring &source_class_name, std::wstring &&source_method_name);
    LogRecord(const Logger &logger, LogLevel level, const std::wstring &message, std::wstring &&source_class_name, std::wstring &&source_method_name);
    LogRecord(const Logger &logger, LogLevel level, std::wstring &&message, std::wstring &&source_class_name, std::wstring &&source_method_name);
    ...
private:
    std::wstring message, source_class_name, source_method_name;
    ...
};

---

ここでは、読みやすくするために簡略化した形式を示します。 Objectはメンバーを持つクラスであり、メンバーMemberの型名です。このMember型には、コピー コンストラクターとムーブ コンストラクターの両方が定義されています。

基本的に、私の質問は、コードの重複を少なくして次のことを行う方法でした。

class Object {
public:
    Object(const Member &x, const Member &y, const Member &z) : x(x), y(y), z(z) {}
    Object(Member &&x, const Member &y, const Member &z) : x(x), y(y), z(z) {}
    Object(const Member &x, Member &&y, const Member &z) : x(x), y(y), z(z) {}
    Object(Member &&x, Member &&y, const Member &z) : x(x), y(y), z(z) {}
    Object(const Member &x, const Member &y, Member &&z) : x(x), y(y), z(z) {}
    Object(Member &&x, const Member &y, Member &&z) : x(x), y(y), z(z) {}
    Object(const Member &x, Member &&y, Member &&z) : x(x), y(y), z(z) {}
    Object(Member &&x, Member &&y, Member &&z) : x(x), y(y), z(z) {}
private:
    Member x, y, z;
}