2

実際、私は SQL XML パスの初心者なので、プロになります。シナリオを手に入れました...次のような CTE 関数があります。

Data    Chars   NumberOfOccurance
12  1   1 appears (1 ) times
12  2   2 appears (1 ) times
xx  x   x appears (2 ) times

CTE関数は次のとおりです。

  ;with cte as
    (
        select Data , SUBSTRING(Data,1,1) as Chars,1 as startpos from @t
        union all
        select Data, SUBSTRING(Data, startpos+1,1) as char,startpos+1 from cte where startpos+1<=LEN(data)
    )
    select Data,Chars,Cast(Chars as varchar(1)) + ' appears (' + cast(COUNT(*) as varchar(5))+  ' ) times' as 'NumberOfOccurance' from cte 
    group by data, chars

実際、私は自分の答えをこれにしたいだけです:

data    Number_of_occurances
12  1 appears (1) times 2 appears (1) times
xx  x appears (2) times

私はこれを試しました：

; With Ctea as 
(
select Data , SUBSTRING(Data,1,1) as Chars,1 as startpos from @t
    union all
    select Data, SUBSTRING(Data, startpos+1,1) as char,startpos+1 from ctea where startpos+1<=LEN(data)
)
select Data,Chars,REPLACE((SELECT (Cast(Chars as varchar(1)) + ' appears (' + cast(COUNT(*) as varchar(5))+ ' ) times') AS [data()] FROM Ctea t2 WHERE t2.Data = t1.data FOR XML PATH('')), ' ', ' ;') As Number_of_occurances  from ctea as t1
group by t1.data, t1.Chars

それは言います：

Column 'Ctea.Chars' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

一時テーブルを使用して正確な答えを得たが、それができない場合 CTE

誰でも私の結果を作ることができますか?

4

2 に答える 2

2

問題は CTE とは関係ありません。実際には、次のサブクエリにあります。

SELECT (Cast(Chars as varchar(1)) + 
    ' appears (' + 
    cast(COUNT(*) as varchar(5)) + 
    ' ) times') AS [data()] 
FROM Ctea t2 
WHERE t2.Data = t1.data 
FOR XML PATH('')

COUNT(*)ここでの集計と列の使用方法に注意してくださいChars。少なくともCharsここでグループ化する必要があります。

SELECT (Cast(Chars as varchar(1)) + 
    ' appears (' + 
    cast(COUNT(*) as varchar(5)) + 
    ' ) times') AS [data()] 
FROM Ctea t2 
WHERE t2.Data = t1.data 
GROUP BY t2.Chars
FOR XML PATH('')

さらに、外側のクエリで選択またはグループ化する必要はありませんt1.Chars。これは、Chars の値ごとに 1 行になるためです。

データ文字 Number_of_occurances
12 1 1が出る(1)回 2が出る(1)回
12 2 1が出る(1)回 2が出る(1)回
xx xx が (2) 回出現

最後に、スペースで区切られたリスト (" 1 が (1) 回表示される 2 が (1) 回表示される") を作成しようとしているため、ではなくSTUFF関数を使用する必要があり、すべてのスペース文字をスペースに置き換えず、セミコロン (" 1 ;出現 ;(1) ;回 ;2 ;出現 ;(1) ;回")。REPLACE

したがって、最終的なクエリは次のようになります。

; With Ctea as 
(
    select Data , SUBSTRING(Data,1,1) as Chars,1 as startpos from @t
    union all
    select Data, SUBSTRING(Data, startpos+1,1) as char,startpos+1 from ctea 
    where startpos+1<=LEN(data)
)
select Data,
    STUFF((SELECT cast(' ' as varchar(max)) + (Cast(Chars as varchar(1)) + ' appears (' + cast(COUNT(*) as varchar(5))+ ' ) times') AS [data()] 
           FROM Ctea t2 
           WHERE t2.Data = t1.data 
           GROUP BY t2.Chars 
           FOR XML PATH('')), 1, 1, '') As Number_of_occurances  
from ctea as t1
group by t1.data
于 2015-05-29T06:03:26.277 に答える
0

FOR XML PATHこのように連結に使用できます

  ;with cte as
    (
        select Data , SUBSTRING(Data,1,1) as Chars,1 as startpos from @t
        union all
        select Data, SUBSTRING(Data, startpos+1,1) as char,startpos+1 from cte where startpos+1<=LEN(data)
    ), CTE2 AS
    (
    select Data,Chars,Cast(Chars as varchar(1)) + ' appears (' + cast(COUNT(*) as varchar(5))+  ' ) times' as 'NumberOfOccurance' from cte 
    group by data, chars
    )
    SELECT Data,(SELECT NumberOfOccurance + ' ' FROM CTE2 c2 WHERE c2.Data = C1.Data FOR XML PATH(''),type).value('.','VARCHAR(MAX)') as Number_of_occurances 
    FROM CTE2 C1
    GROUP BY Data
于 2015-05-29T06:03:09.370 に答える