1

クエリでロジックの問題に直面しています。

と の 2 つのテーブルがありTable1ます。Table2Table1

  • value 合計される
  • Id によってグループ化される
  • Code 外部キーを保持Table2

そしてTable2、

  • Code
  • Des コードのテキスト記述

私がやろうとしているのは、 group by Table1.Id、 full join onTable2.Codeですが、結果のグループごとに、クエリによって生成されたグループごとに Table2 のすべての行を表示したいと考えています。

サンプルコード:

SELECT
    Table2.Code, Table1.Id, Table2.DES, 
    SUM(Table1.Value) AS SUM_VAL
FROM 
(
    SELECT 'A' AS Code, 1 AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'A' AS Code, 2 AS Id, 20 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 1 AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 1 AS Id, 30 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 2 AS Id, 50 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 1 AS Id, 40 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 2 AS Id, 60 AS Value FROM DUAL UNION
    SELECT 'D' AS Code, 1 AS Id, 20 AS Value FROM DUAL

) Table1
FULL JOIN
(
    SELECT 'A' AS Code, 'This is A' AS DES FROM DUAL UNION
    SELECT 'B' AS Code, 'This is B' AS DES FROM DUAL UNION
    SELECT 'C' AS Code, 'This is C' AS DES FROM DUAL UNION
    SELECT 'D' AS Code, 'This is D' AS DES FROM DUAL
) Table2
ON Table1.Code = Table2.Code
GROUP BY
    Table2.Code, Table1.Id, Table2.DES
ORDER BY
    Table2.Code, Table1.Id ASC

結果：

A   1   This is A   10
A   2   This is A   20
B   1   This is B   40
B   2   This is B   50
C   1   This is C   40
C   2   This is C   60
D   1   This is D   20

必要な結果:

A   1   This is A   10
A   2   This is A   20
B   1   This is B   40
B   2   This is B   50
C   1   This is C   40
C   2   This is C   60
D   1   This is D   20
D   2   This is D   0    <- This is the target
4

3 に答える 3

1

id と value のすべての組み合わせが必要な場合は、 を使用cross joinして行を取得し、 aleft joinを使用して残りの値を取り込みます。

select t2.code, i.value, t2.desc, coalesce(cnt, 0) as cnt
from (select distinct id from table1) i cross join
     table2 t2 left join
     (select id, value, count(*) as cnt
      from table1
      group by id, value
     ) iv
     on iv.id = i.id and iv.code = t2.code

これは、すべての組み合わせを手動でリストするよりもはるかに簡単です。

于 2015-06-10T10:50:56.530 に答える
1 
SELECT
    Table2.Code, Table2.NAT, Table2.DES, 
    SUM(Table1.Value) AS SUM_VAL
FROM 
(
    SELECT 'A' AS Code, 'QA' AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'A' AS Code, 'NQA' AS Id, 20 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 'QA' AS Id, 10 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 'QA' AS Id, 30 AS Value FROM DUAL UNION
    SELECT 'B' AS Code, 'NQA' AS Id, 50 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 'QA' AS Id, 40 AS Value FROM DUAL UNION
    SELECT 'C' AS Code, 'NQA' AS Id, 60 AS Value FROM DUAL UNION
    SELECT 'D' AS Code, 'QA' AS Id, 20 AS Value FROM DUAL

) Table1
FULL JOIN
(
    SELECT 'QA' NAT,'A' AS Code, 'This is A' AS DES FROM DUAL UNION
    SELECT 'QA' NAT,'B' AS Code, 'This is B' AS DES FROM DUAL UNION
    SELECT 'QA' NAT,'C' AS Code, 'This is C' AS DES FROM DUAL UNION
    SELECT 'QA' NAT,'D' AS Code, 'This is D' AS DES FROM DUAL
    UNION
    SELECT 'NQA' NAT,'A' AS Code, 'This is A' AS DES FROM DUAL UNION
    SELECT 'NQA' NAT,'B' AS Code, 'This is B' AS DES FROM DUAL UNION
    SELECT 'NQA' NAT,'C' AS Code, 'This is C' AS DES FROM DUAL UNION
    SELECT 'NQA' NAT,'D' AS Code, 'This is D' AS DES FROM DUAL
) Table2
on TABLE2.NAT = TABLE1.ID
      AND Table2.Code= Table1.Code
GROUP BY
    Table2.Code, Table2.NAT, Table2.DES
ORDER BY
    Table2.Code, Table2.NAT ASC
于 2015-06-11T05:14:21.660 に答える