Warning:mysql_fetch_array(): supplied argument is not a valid MySQL result resource in **/home/davzyco1/public_html/notes/functions.php** on line 43
クラスが古いWebホストで完全に機能しているにもかかわらず、以下のクラスを使用したときに発生したエラーでした。ここに私の新しいホスト php 情報があります: http://davzy.com/notes/php.php
class mysqlDb
{
public $con;
public $debug;
function __construct($host,$username,$password,$database)
{
$this->con = mysql_connect($host,$username,$password);
if (!$this->con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($database, $this->con);
}
function kill()
{
mysql_close($this->con);
}
function debugOn()
{
$this->debug = true;
}
function debugOff()
{
$this->debug = false;
}
function select($query,&$array)
{
$c = 0;
$result = mysql_query("SELECT ".$query);
if($this->debug == true)
echo "SELECT ".$query;
while($row = mysql_fetch_array($result))
{
foreach($row as $id => $value)
{
$array[$c][$id] = $value;
}
$c++;
}
}
function update($update, $where,$array)
{
foreach($array as $id => $value)
{
mysql_query("UPDATE {$update} SET {$id} = '{$value}'
WHERE {$where}");
if($this->debug == true)
echo "UPDATE {$update} SET {$id} = '{$value}'
WHERE {$where}<br><br>";
}
}
function updateModern($update, $where,$array)
{
foreach($array as $id => $value)
{
mysql_query("UPDATE {$update} SET `{$id}` = '{$value}'
WHERE {$where}");
if($this->debug == true)
echo "UPDATE {$update} SET {$id} = '{$value}'
WHERE {$where}<br>";
}
}
function delete($t, $w)
{
mysql_query("DELETE FROM `{$t}` WHERE {$w}");
if($this->debug == true)
echo "DELETE FROM `{$t}` WHERE {$w}<br><br>";
}
function insert($where, $array)
{
$sql = "INSERT INTO `{$where}` (";
$sql2 = " VALUES (";
foreach($array as $id => $value){
$sql .= "`{$id}`, ";
$sql2 .= "'{$value}', ";
}
mysql_query(str_replace(', )',')',$sql.")") . str_replace(', )',')',$sql2.");"));
if($this->debug == true)
echo str_replace(', )',')',$sql.")") . str_replace(', )',')',$sql2.");")."<br><br>";
}
}