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Entity Framewrok 6.0 によって生成された以下のクエリに問題があります。where句クエリを削除すると、うまく実行されています。しかし、where句の問題はわかりません。手伝ってくれませんか?

{SELECT 
"Extent1"."ID" AS "ID", 
"Extent1"."STATECODE" AS "STATECODE", 
"Extent1"."FIRMAID" AS "FIRMAID", 
"Extent1"."ILID" AS "ILID", 
"Extent1"."ILCEID" AS "ILCEID", 
"Extent1"."PLANTURID" AS "PLANTURID", 
"Extent1"."ETUDTURID" AS "ETUDTURID", 
"Extent1"."ETUDAMACID" AS "ETUDAMACID", 
"Extent1"."DILIMID" AS "DILIMID", 
"Extent1"."ACIKLAMA" AS "ACIKLAMA", 
"Extent1"."BASVURUTARIHI" AS "BASVURUTARIHI", 
"Extent1"."ALAN" AS "ALAN", 
"Extent1"."OLCEK" AS "OLCEK", 
"Extent1"."CREATETIME" AS "CREATETIME", 
"Extent1"."UPDATETIME" AS "UPDATETIME", 
"Extent1"."CREATEUSERID" AS "CREATEUSERID", 
"Extent1"."UPDATEUSERID" AS "UPDATEUSERID", 
"Extent2"."ID" AS "ID1", 
"Extent2"."KOD" AS "KOD", 
"Extent2"."AD" AS "AD", 
"Extent2"."CREATETIME" AS "CREATETIME1", 
"Extent2"."UPDATETIME" AS "UPDATETIME1", 
"Extent2"."CREATEUSERID" AS "CREATEUSERID1", 
"Extent2"."UPDATEUSERID" AS "UPDATEUSERID1", 
"Extent3"."ID" AS "ID2", 
"Extent3"."KOD" AS "KOD1", 
"Extent3"."AD" AS "AD1", 
"Extent3"."PLANTURID" AS "PLANTURID1", 
"Extent3"."CREATETIME" AS "CREATETIME2", 
"Extent3"."UPDATETIME" AS "UPDATETIME2", 
"Extent3"."CREATEUSERID" AS "CREATEUSERID2", 
"Extent3"."UPDATEUSERID" AS "UPDATEUSERID2", 
"Extent4"."ID" AS "ID3", 
"Extent4"."VERGINUMARASI" AS "VERGINUMARASI", 
"Extent4"."EMAIL" AS "EMAIL", 
"Extent4"."FIRMAADI" AS "FIRMAADI", 
"Extent4"."BUROTESCILNUMARASI" AS "BUROTESCILNUMARASI", 
"Extent4"."TELEFON" AS "TELEFON", 
"Extent4"."ADRES" AS "ADRES", 
"Extent4"."ILID" AS "ILID1", 
"Extent4"."ILCEID" AS "ILCEID1", 
"Extent4"."MAHALLEID" AS "MAHALLEID", 
"Extent4"."VERGIDAIRESIID" AS "VERGIDAIRESIID", 
"Extent4"."USERID" AS "USERID", 
"Extent4"."NODEID" AS "NODEID", 
"Extent4"."CREATETIME" AS "CREATETIME3", 
"Extent4"."UPDATETIME" AS "UPDATETIME3", 
"Extent4"."CREATEUSERID" AS "CREATEUSERID3", 
"Extent4"."UPDATEUSERID" AS "UPDATEUSERID3", 
"Extent5"."FEATUREID" AS "FEATUREID", 
"Extent5"."ADI_NUMARASI" AS "ADI_NUMARASI", 
"Extent5"."UAVTKOD" AS "UAVTKOD", 
"Extent6"."FEATUREID" AS "FEATUREID1", 
"Extent6"."ADI_NUMARASI" AS "ADI_NUMARASI1", 
"Extent6"."UAVTKOD" AS "UAVTKOD1", 
"Extent6"."ILKOD" AS "ILKOD", 
"Extent7"."ID" AS "ID4", 
"Extent7"."ENLEM" AS "ENLEM", 
"Extent7"."BOYLAM" AS "BOYLAM", 
"Extent7"."DILIMI" AS "DILIMI", 
"Extent7"."MERIDYEN" AS "MERIDYEN", 
"Extent7"."ILADI" AS "ILADI", 
"Extent7"."ILID" AS "ILID2", 
"Extent8"."ID" AS "ID5", 
"Extent8"."KOD" AS "KOD2", 
"Extent8"."AD" AS "AD2", 
"Extent8"."CREATETIME" AS "CREATETIME4", 
"Extent8"."UPDATETIME" AS "UPDATETIME4", 
"Extent8"."CREATEUSERID" AS "CREATEUSERID4", 
"Extent8"."UPDATEUSERID" AS "UPDATEUSERID4"
FROM        "JEOLOJI"."PROJE" "Extent1"
INNER JOIN "JEOLOJI"."ETUDAMAC" "Extent2" ON "Extent1"."ETUDAMACID" = "Extent2"."ID"
INNER JOIN "JEOLOJI"."ETUDTUR" "Extent3" ON "Extent1"."ETUDTURID" = "Extent3"."ID"
INNER JOIN "JEOLOJI"."FIRMA" "Extent4" ON "Extent1"."FIRMAID" = "Extent4"."ID"
INNER JOIN "JEOLOJI"."IL" "Extent5" ON "Extent1"."ILID" = "Extent5"."FEATUREID"
LEFT OUTER JOIN "JEOLOJI"."ILCE" "Extent6" ON "Extent1"."ILCEID" = "Extent6"."FEATUREID"
INNER JOIN "JEOLOJI"."DILIM" "Extent7" ON "Extent1"."DILIMID" = "Extent7"."ID"
INNER JOIN "JEOLOJI"."PLANTUR" "Extent8" ON "Extent1"."PLANTURID" = "Extent8"."ID"
WHERE ((1 = (CASE WHEN (( NVL(INSTR(LOWER(CASE WHEN ("Extent1"."ACIKLAMA" IS NULL) THEN '' ELSE "Extent1"."ACIKLAMA" END), LOWER('Ma')), 0) ) = 1) THEN 1 WHEN (( NVL(INSTR(LOWER(CASE WHEN ("Extent1"."ACIKLAMA" IS NULL) THEN '' ELSE "Extent1"."ACIKLAMA" END), LOWER('Ma')), 0) ) <> 1) THEN 0 END)) AND (22 <> "Extent1"."FIRMAID"))}
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1 に答える 1

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問題を解決しました。

Entity FrameworkがOracleの列として作成するのを防ぐためstringに、c#で型を属性でマークしています。次に、Entity Frameworkは、属性でマークされた c# プロパティの型を持つ列を生成します。StringLengthNCLOBnvarcharStringLenth

このクエリでは、qoutes のおかげでwherevarchar2が正常に機能します (Db の職業上の友人から学んだように)。そのため、列の型を変更して解決しました。

于 2015-07-10T14:47:00.560 に答える