sql - SQLクエリ従業員の名前とそれに対応する部門を表示します

Question

以下は私のCREATE TABLEスクリプトです：

CREATE TABLE Person 
( 
   ID INT Primary Key Identity (1,1), 
   LastName nVarchar (20) not NULL, 
   FirstName nVarchar (20) not NULL, 
   MiddleName nVarchar (20), 
   BirthDate DateTime not NULL, 
   Age INT not NULL, 
   Check (Age18) 
); 

CREATE TABLE Department 
( 
   ID INT Primary Key Identity (1,1), 
   DepartmentName nVarchar (50) Unique, 
   DepartmentCode nVarchar (20) Unique, 
   IsActive Bit Default (1) 
); 

CREATE TABLE Employee 
( 
   ID INT Primary Key Identity (1,1), 
   PersonId INT Foreign Key REFERENCES Person, 
   DepartmentId INT Foreign Key REFERENCES Department, 
   Salary Decimal (18,2), 
   Check (Salary10000), 
   IsActive Bit Default (1) 
);

以下は私のINSERTスクリプトです：

INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Dela Cruz','Juan',NULL,01/01/199,22) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Dela Cerna','Pedro','Juan',11/01/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Villaflores','Rachel','Diacoma',10/7/1990,24) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Abendan','Marnell',NULL,03/15/1989,25) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Oplado','Aiza','Tapayan',11/18/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Loreto','Desire','Talingting',06/10/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Magbanua','Prince Laurence','Rallos',05/25/1992,22) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Locsin','Franz Cyril',NULL,02/14/1993,21) 
INSERT INTO Person (LastName, FirstName, MiddleName,BirthDate,Age) 
VALUES ('Dela Pena','Precious',NULL,01/01/199,21) 

 INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('ITDepartment','ItDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('EngineeringDepartment','EDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('ComputerScienceDepartment','CSDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('InformationSystemDepartment','ISDept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('BusinessAdministrationDepartment','BADept',1) 
INSERT INTO Department (DepartmentName, DepartmentCode, IsActive) 
VALUES ('ElementaryDepartment','ElemDept',1) 

 INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (1,2,12000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (2,4,10001,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (3,6,13000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (4,1,25000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (5,3,15000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (6,5,10002,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (7,1,56000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (8,4,14000,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (9,6,15900,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (2,4,12300,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (4,1,13500,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (6,3,14300,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (8,5,12500,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (1,2,11460,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (3,4,10910,1) 
INSERT INTO Employee (PersonId,DepartmentId,Salary,IsActive) 
VALUES (5,6,10001,1)

以下は私の選択スクリプトです：

SELECT 
    Person.LastName, Department.DepartmentName 
FROM 
    Person, Department 
FULL OUTER JOIN 
    Employee ON Employee.PersonId = Employee.DepartmentId

これは正しくない結果です。これには何が正しいのかわかりません。JOINSは初めてです。

Dela Cruz   BusinessAdministrationDepartment 
Dela Cerna  BusinessAdministrationDepartment 
Villaflores BusinessAdministrationDepartment 
Abendan BusinessAdministrationDepartment 
Oplado  BusinessAdministrationDepartment 
Loreto  BusinessAdministrationDepartment 
Magbanua    BusinessAdministrationDepartment 
Locsin  BusinessAdministrationDepartment 
Dela Pena   BusinessAdministrationDepartment 
Dela Cruz   ComputerScienceDepartment 
Dela Cerna  ComputerScienceDepartment 
Villaflores ComputerScienceDepartment 
Abendan ComputerScienceDepartment 
Oplado  ComputerScienceDepartment 
Loreto  ComputerScienceDepartment 
Magbanua    ComputerScienceDepartment 
Locsin  ComputerScienceDepartment 
Dela Pena   ComputerScienceDepartment

長くなりすぎるので、コンピューターサイエンス部門に立ち寄りました。どうすればこれを正しく理解できますか? 助けてください。ありがとう！:)

score 2 · Accepted Answer

あなたはこれを探していますか:-

Select  p.LastName, d.DepartmentName
From    Employee As e
        Join Person As p On e.PersonId = p.Id
        JOin Department As d On e.DepartmentId = d.ID

score 1 · Accepted Answer

SELECT Person.LastName, Department.DepartmentName FROM Employee INNER JOIN Person ON Employee.PersonId = Person.ID INNER JOIN Department ON Employee.DepartmentId = Department.ID

sql - SQLクエリ従業員の名前とそれに対応する部門を表示します

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