私の状況では、注文や注文の詳細など、1対多の関係があり、単一の注文の詳細を持つ注文を取得する必要があります。
2 に答える
0
How about:
select *
from order
where order_number in
(select order_number
from order_details
group by order_number
having count(*) = 1)
于 2010-06-30T07:18:39.043 に答える
0
SELECT O1.order_number
FROM Orders AS O1
WHERE 1 = (
SELECT COUNT(*)
FROM OrderDetails AS D1
WHERE O1.order_number = D1.order_number
);
于 2010-06-30T08:48:52.003 に答える