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製品表

CREATE TABLE product(
Product_id varchar(7) NOT NULL PRIMARY KEY,
Product_name varchar(40),
Product_type varchar(10)
);


INSERT INTO Product VALUES
('P001','Apple Cinnamon Cereal','Cereal'),
('P002','Chocolate Almond Cereal','Cereal'),
('P003','Chocolate Delight Cereal','Cereal'),
('P004','Chocolate Mocha Protein Shake','Beverage'),
('P005','Vanilla Cappuccino Protein Shake','Beverage'),
('P006','Multi-grain Crackers','Cracker'),
('P007','Chili Lime Cracker Chips ','Cracker');

売上表

CREATE TABLE Sales(
Time_id varchar(6) NOT NULL ,
Product_id varchar(7) NOT NULL,
Saler_id varchar(10) not null,
Cust_id varchar(10) NOT NULL,
Sales_quantity int, 
Cost_sales decimal(5,2),
Primary key(Time_id,Product_id,Cust_id,Saler_id),
Foreign key (Time_id) references Time,
Foreign key (Product_id) references Product,
Foreign key (Saler_id) references Wholesaler,
Foreign key (Cust_id) references Customer);




insert into Sales values
('T001','P001','W002','C001',3,9.50),
('T003','P003','W005','C002',2,8.50),
('T004','P002','W001','C003',4,9.60),
('T005','P001','W004','C004',3,8.90),
('T003','P004','W001','C003',3,8.50),
('T002','P004','W001','C003',4,9.50)

顧客テーブル

CREATE TABLE customer(
Cust_idvarchar(10) NOT NULL PRIMARY KEY,
Cust_namevarchar(20),
Cust_gendervarchar(6),
Cust_DOB date,
Cust_addressvarchar(100)
)
INSERT INTO customer values
('C001','David Tan','Female','1992-06-18','Cyberia A2-4-5, PSN Multimedia, 63000 Cyberjaya, Selangor'),
('C002','Ariel Lin','Female','1987-07-23','Cyberia E-33-5, PSN Multimedia, 63000 Cyberjaya, Selangor'),
('C003','Kobe','Male','1992-06-18','Cyberia A2-4-5, PSN Multimedia, 63000 Cyberjaya, Selangor'),
('C004','Kelvin Tan','Male','1989-03-01','Cyberia B3-4-5, PSN Multimedia, 63000 Cyberjaya, Selangor'),

この 3 つのテーブルを結合して、結合またはサブクエリを使用して以下のような出力を生成するにはどうすればよいですか...

顧客名 | アイテム購入回数 | 最も頻繁な製品タイプ

神戸 ,3 ,飲料

select customer.cust_name,count(sales.cust_id),max(product.product_type) from
(Sales
Inner join customer
On Customer.cust_id=Sales.cust_id
Inner join product
On Product.product_id=Sales.product_id)
Group by cust_name;

私の試行コードですが、3番目の1 hvの問題

4

1 に答える 1

0

group by を使用して 3 つのテーブルを内部結合します。これを試して

select Cust_name, sum( Sales_quantity) Bought , Product_name
from customer c inner join  Sales s on c.Cust_id=s.Cust_id
inner join Product p on s.Product_id=p.Product_id
group by c.Cust_name,p.Product_name

http://www.sqlfiddle.com/#!3/b835e/5で確認してください

于 2015-09-12T12:36:17.143 に答える