stackoverflow に関する質問「Slimphp で GUMP を使用してデータを検証する」がありますが、この質問は重複していません。
GUMP PHP 入力検証クラスを使用してフォーム データ ( https://github.com/Wixel/GUMPで入手可能) を検証したいのですが、それをフォームに追加する方法がわかりませんでした。
これはかなり単純なGUMPの例です
<?php
require "../gump.class.php";
$validator = new GUMP();
// Set the data
$_POST = array(
'username' => 'Sisi',
'password' => 'mypassword',
'email' => 'sean@wixel.net',
'gender' => 'm',
'bio' => 'This is good! I think I will switch to another language');
$_POST = $validator->sanitize($_POST); // You don't have to sanitize, but it's safest to do so.
// Let's define the rules and filters
$rules = array(
'username' => 'required|alpha_numeric|max_len,100|min_len,6',
'password' => 'required|max_len,100|min_len,6',
'email' => 'required|valid_email',
'gender' => 'required|exact_len,1',
'bio' => 'required');
$filters = array(
'username' => 'trim|sanitize_string',
'password' => 'trim|base64_encode',
'email' => 'trim|sanitize_email',
'gender' => 'trim');
$_POST = $validator->filter($_POST, $filters);
// You can run filter() or validate() first
$validated = $validator->validate($_POST, $rules);
// Check if validation was successful
if($validated === TRUE)
{
echo "Successful Validation\n\n";
print_r($_POST); // You can now use POST data safely
exit;
}else{
// You should know what form fields to expect, so you can reference them here for custom messages
echo "There were errors with the data you provided:\n";
// Or you can simply use the built in helper to generate the error messages for you
// Passing a boolean true to is returns the errors as html, otherwise it returns an array
echo $validator->get_readable_errors(true);
}
ここで、テスト目的で作成したデモ フォームで、ユーザー名とパスワードを収集して印刷します
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$user_name = $_POST["user_name"];
$user_password = $_POST["user_password"];
echo $user_name;
echo $user_password;
}
私はこれを交換する必要があることを知っています
$_POST = array('username' => 'Sisi', 'password' => 'mypassword', 'email' => sean@wixel.net', 'gender' => 'male', 'bio' => 'This is good! I think I will switch to another language');
と
$user_name = $_POST["user_name"]; $user_password = $_POST["user_password"];
しかし、単にできません。
手伝ってくれますか?