私は以下のようにテーブルConfigManagementSettingsと外部からテーブルを持ってDeviceGroupいます:
@Entity
@Table(name = "device_group")
public class DeviceGroup extends devicemanage.repository.base.entity.base.EntityBase implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(unique = true, nullable = false)
private Long id;
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "create_time", nullable = false)
private Calendar createTime;
@Column(name = "domain_id", nullable = false)
private int domainId;
@Column(nullable = false)
private String name;
private String remark;
@Column(nullable = false)
private Integer type;
@Version
private Integer version;
@OneToOne(cascade = CascadeType.ALL, mappedBy = "deviceGroupParent", fetch = FetchType.LAZY)
private ConfigManagementSettings configManagementCollection;
}
@Entity
@Table(name = "config_management_settings")
public class ConfigManagementSettings extends EntityBase implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(unique = true, nullable = false)
private Long id;
@Version
private Integer version;
@Column(name = "group_id", nullable = false, unique = true)
private Long groupId;
private byte[] settings;
@Column(name = "sequential_order", nullable = false)
private Integer sequentialOrder;
@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "group_id")
private DeviceGroup deviceGroupParent;
@Transient
private int order;
}
以下のように単純な単体テストを行うと
@Test
public void testConfigManagementSettings() throws Exception
{
ConfigManagementSettings config = new ConfigManagementSettings();
config.setGroupId(3L);
config.setSequentialOrder(1);
configManagementSettingsDao.save(config);
}
以下のように InvalidStateException を取得しました
Caused by: <openjpa-2.2.2-r422266:1468616 fatal general error> org.apache.openjpa.persistence.PersistenceException: The transaction has been rolled back. See the nested exceptions for details on the errors that occurred.
at org.apache.openjpa.kernel.BrokerImpl.newFlushException(BrokerImpl.java:2347)
at org.apache.openjpa.kernel.BrokerImpl.flush(BrokerImpl.java:2184)
at org.apache.openjpa.kernel.BrokerImpl.flushSafe(BrokerImpl.java:2082)
at org.apache.openjpa.kernel.BrokerImpl.beforeCompletion(BrokerImpl.java:2000)
at org.apache.openjpa.kernel.LocalManagedRuntime.commit(LocalManagedRuntime.java:81)
at org.apache.openjpa.kernel.BrokerImpl.commit(BrokerImpl.java:1524)
at org.apache.openjpa.kernel.DelegatingBroker.commit(DelegatingBroker.java:933)
at org.apache.openjpa.persistence.EntityManagerImpl.commit(EntityManagerImpl.java:570)
at org.springframework.orm.jpa.JpaTransactionManager.doCommit(JpaTransactionManager.java:515)
... 45 more
Caused by: <openjpa-2.2.2-r422266:1468616 fatal user error> org.apache.openjpa.persistence.InvalidStateException: Attempt to set column "config_management_settings.group_id" to two different values: (null)"null", (class java.lang.Long)"3" This can occur when you fail to set both sides of a two-sided relation between objects, or when you map different fields to the same column, but you do not keep the values of these fields in synch.
at org.apache.openjpa.jdbc.sql.PrimaryRow.setObject(PrimaryRow.java:344)
at org.apache.openjpa.jdbc.sql.RowImpl.setObject(RowImpl.java:510)
at org.apache.openjpa.jdbc.meta.strats.HandlerStrategies.set(HandlerStrategies.java:158)
at org.apache.openjpa.jdbc.meta.strats.HandlerStrategies.set(HandlerStrategies.java:109)
at org.apache.openjpa.jdbc.meta.strats.HandlerFieldStrategy.insert(HandlerFieldStrategy.java:130)
at org.apache.openjpa.jdbc.meta.FieldMapping.insert(FieldMapping.java:623)
at org.apache.openjpa.jdbc.kernel.AbstractUpdateManager.insert(AbstractUpdateManager.java:239)
at org.apache.openjpa.jdbc.kernel.AbstractUpdateManager.populateRowManager(AbstractUpdateManager.java:166)
at org.apache.openjpa.jdbc.kernel.AbstractUpdateManager.flush(AbstractUpdateManager.java:97)
at org.apache.openjpa.jdbc.kernel.AbstractUpdateManager.flush(AbstractUpdateManager.java:78)
at org.apache.openjpa.jdbc.kernel.JDBCStoreManager.flush(JDBCStoreManager.java:732)
at org.apache.openjpa.kernel.DelegatingStoreManager.flush(DelegatingStoreManager.java:131)
... 53 more
ただし、以下のように、別の 2 つのテーブル Subtask と SubtaskResult もあります。
@Entity
@Table(name = "subtask")
public class Subtask extends devicemanage.repository.base.entity.base.EntityBase implements Serializable
{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(unique = true, nullable = false)
private Long id;
@Column(name = "domain_id", nullable = false)
private Integer domainId;
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "finish_time")
private Calendar finishTime;
@Column(nullable = false)
private Integer state;
@Column(name = "task_id", nullable = false)
private Long taskId;
@Column(name = "task_type", nullable = false, length = 1)
private String taskType;
@Column(length = 256)
private String remark;
// @Version
private Integer version;
@OneToOne(cascade = CascadeType.ALL, mappedBy = "subtaskParent", fetch = FetchType.LAZY)
private SubtaskResult resultOfSubtask;
}
@Entity
@Table(name = "subtask_result")
public class SubtaskResult extends EntityBase implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(unique = true, nullable = false)
private Long id;
@Version
private Integer version;
@Column(name = "subtask_id", unique=true, nullable = false)
private Long subtaskId;
private String results;
@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "subtask_id")
private Subtask subtaskParent;
}
また、以下のように行った単純な単体テスト
@Test
public void testSubtaskResult() throws Exception
{
SubtaskResult subtaskResult = new SubtaskResult();
subtaskResult.setSubtaskId(33L);
subtaskResult.setResults("test");
subtaskResultDao.save(subtaskResult);
}
エンティティを永続化するために正常に機能します。
私が見逃しているものはありますか？これら 2 つのケースの動作が異なるのはなぜですか?
どんな助けでも大歓迎です。