以下の例によると: 値は A1 にのみ格納され、他のセルは nil を返します。他のマージされたセルから A1'a 値を取得する方法、または単に A1 セルの範囲を確認する方法はありますか?
2 に答える
0
すべてのマージされたフィールドが前と同じ場合、マージされていないフィールドは配列になるはずです
xlsx = Roo::Excelx.new(__dir__ + "/output.xlsx", { expand_merged_ranges: true })
parsed = xlsx.sheet(0).parse(headers: true).drop(1)
parsed_merged = []
.tap do |parsed_merged|
parsed.each do |x|
if parsed_merged.empty?
parsed_merged << {
"field_non_merged1" => x["field_non_merged1"],
"field_merged1" => [x["field_merged1"]],
"field_merged2" => [x["field_merged2"]],
"field_merged3" => [x["field_merged3"]],
"field_merged4" => [x["field_merged4"]],
"field_non_merged2" => x["field_non_merged2"],
"field_non_merged3" => x["field_non_merged3"],
}
else
field_merged1_is_same_as_prev = x["field_non_merged1"] == parsed_merged.last["field_non_merged1"]
field_merged2_is_same_as_prev = x["field_non_merged2"] == parsed_merged.last["field_non_merged2"]
field_merged3_is_same_as_prev = x["field_non_merged3"] == parsed_merged.last["field_non_merged3"]
merged_rows_are_all_same_as_prev = field_non_merged1_is_same_as_prev && field_merged2_is_same_as_prev && field_merged3_is_same_as_prev
if merged_rows_are_all_same_as_prev
parsed_merged.last["field_merged1"].push x["field_merged1"]
parsed_merged.last["field_merged2"].push x["field_merged2"]
parsed_merged.last["field_merged3"].push x["field_merged3"]
parsed_merged.last["field_merged4"].push x["field_merged4"]
else
parsed_merged << {
"field_non_merged1" => x["field_non_merged1"],
"field_merged1" => [x["field_merged1"]],
"field_merged2" => [x["field_merged2"]],
"field_merged3" => [x["field_merged3"]],
"field_merged4" => [x["field_merged4"]],
"field_non_merged2" => x["field_non_merged2"],
"field_non_merged3" => x["field_non_merged3"],
}
end
end
end
end
.map do |x|
{
"field_non_merged1" => x["field_non_merged1"],
"field_merged1" => x["field_merged1"].compact.uniq,
"field_merged2" => x["field_merged2"].compact.uniq,
"field_merged3" => x["field_merged3"].compact.uniq,
"field_merged4" => x["field_merged4"].compact.uniq,
"field_non_merged2" => x["field_non_merged2"],
"field_non_merged3" => x["field_non_merged3"],
}
end
于 2020-02-14T13:24:06.297 に答える