0

これは私の質問です。

SELECT SQL_CALC_FOUND_ROWS (FOUND_ROWS() ) as total, 
(SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization 
WHERE dsp.profileid = pm.id and 
(dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec , 
pm.id as profileid, pm.loginid as loginid, dam.clinicname, dam.area, dam.address, dam.pincode, dam.id as 
addressid, dam.feecharge as feecharge, pm.fname, pm.lname, pm.email, pm.mobile, pm.phone, pm.gender, pm.dob, 
pm.totexp, pm.imagepath, pm.languages, pm.statement, pm.createdby, um.profile_url, um.clinic_url,
pm.hsbit,  (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm LEFT JOIN DAddress_Master dam on dam.profileid = pm.id left join Unique_Url_Master um on 
um.clinicid =dam.id WHERE dam.city='Surat' and pm.id IN (SELECT profileid FROM DSpecialization_Master 
WHERE specialization = (select id from Specialization_master where specialization='Dentist')) ORDER BY pm.id limit 0 , 10

承認された結果はtotal:344、私が得ていると述べられてtotal:1います。

このクエリを実行しましたが、正しい結果が得られています。

select SQL_CALC_FOUND_ROWS id,(FOUND_ROWS() ) as total from unique_url_master1 limit 10;

total:1313

私は何が間違っていますか？参考までに、クエリを中断することはできません。つまり、最初に実行します

SQL_CALC_FOUND_ROWS を選択

そして実行

FOUND_ROWS() を選択

ひどく助けが必要..

編集

クエリを変更し、count(*) 関数を使用しました。今、私は正しいtotal:344を取得していますが、1 行しか返されません。誰かが私を導くことができますか？

SELECT  count(*) as total_count ,
        (SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization WHERE dsp.profileid = pm.id and (dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec, 
        pm.id as profileid, 
        pm.loginid as loginid, 
        dam.clinicname, 
        dam.area, 
        dam.address, 
        dam.pincode, 
        dam.id as addressid, 
        dam.feecharge as feecharge, 
        pm.fname, 
        pm.lname, 
        pm.email, 
        pm.mobile, 
        pm.phone, 
        pm.gender, 
        pm.dob, 
        pm.totexp, 
        pm.imagepath, 
        pm.languages, 
        pm.statement, 
        pm.createdby, 
        um.profile_url, 
        um.clinic_url, 
        pm.hsbit,  
        (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10;

要件の変更により、MSSQLクエリをMYSQlに変換する必要があるため、COUNT(*) OVER()を使用してMSSQLでクエリを実行しています。私はこのようにこれを受け入れている結果これ

4

1 に答える 1

1

COUNTn なしで集計関数を使用しているGROUP BYと、常に 1 行になります。GROUP BY の定義。

2 つの個別のクエリを使用して必要なものを取得する方がはるかに優れています。1 つは他のすべての変数を選択し、もう 1 つはカウントのみを選択します。

すべての行 + 変数

SELECT  (SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization WHERE dsp.profileid = pm.id and (dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec, 
    pm.id as profileid, 
    pm.loginid as loginid, 
    dam.clinicname, 
    dam.area, 
    dam.address, 
    dam.pincode, 
    dam.id as addressid, 
    dam.feecharge as feecharge, 
    pm.fname, 
    pm.lname, 
    pm.email, 
    pm.mobile, 
    pm.phone, 
    pm.gender, 
    pm.dob, 
    pm.totexp, 
    pm.imagepath, 
    pm.languages, 
    pm.statement, 
    pm.createdby, 
    um.profile_url, 
    um.clinic_url, 
    pm.hsbit,  
    (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10;

カウント：

SELECT  count(*) as total_count,
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10;

1 つのクエリで画像のように本当にしたい場合は、次の手順を実行する必要があります。

SELECT T1.overall_count, T2.*
FROM (SELECT COUNT(*) AS overall_count
    FROM Profile_Master pm 
    LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
    LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
    WHERE dam.city='Surat' 
    AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
    ORDER BY pm.id 
    LIMIT 0, 10) AS T1
JOIN ((SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization WHERE dsp.profileid = pm.id and (dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec, 
    pm.id as profileid, 
    pm.loginid as loginid, 
    dam.clinicname, 
    dam.area, 
    dam.address, 
    dam.pincode, 
    dam.id as addressid, 
    dam.feecharge as feecharge, 
    pm.fname, 
    pm.lname, 
    pm.email, 
    pm.mobile, 
    pm.phone, 
    pm.gender, 
    pm.dob, 
    pm.totexp, 
    pm.imagepath, 
    pm.languages, 
    pm.statement, 
    pm.createdby, 
    um.profile_url, 
    um.clinic_url, 
    pm.hsbit,  
    (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10) AS T2
于 2016-04-13T06:42:27.293 に答える