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$A = ["0" => "a", "1" => "b", "2" => "c"];
$B = ["0" => "aa", "1" => "bb", "2" => "cc"]
array_walk($A,function($item) use($B){
     $temp[] = $item;
     $temp[] = $B[?];
});

を埋める方法は?その上?array_walkで現在のインデックスを取得する方法は?

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1 に答える 1

2

私が正しく理解していれば、そのようなことはうまくいくでしょう

$A = ["0" => "a", "1" => "b", "2" => "c"];
$B = ["0" => "aa", "1" => "bb", "2" => "cc"]
array_walk($A,function($item, $key) use($B){
     $temp[] = $item;
     $temp[] = $B[$key];
});
于 2016-09-07T07:29:53.843 に答える