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The problem is that <code> is treated according to the normal rules for HTML markup, and content inside <code> tags is still HTML (The tags exists mainly to drive CSS formatting, not to change the parsing rules).

What you are trying to do is create a different markup language that is very similar, but not identical, to HTML. The simple solution would be to assume certain rules, such as, "<code> and </code> must appear on a line by themselves," and do some pre-processing yourself.

  1. A very simple — though not 100% reliable — technique is to replace ^<code>$ with <code><![CDATA[ and ^</code>$ with ]]></code>. It isn't completely reliable, because if the code block contains ]]>, things will go horribly wrong.
  2. A safer option is to replace dangerous characters inside code blocks (<, > and & probably suffice) with their equivalent character entity references (&lt;, &gt; and &amp;). You can do this by passing each block of code you identify to cgi.escape(code_block).

Once you've completed preprocessing, submit the result to BeautifulSoup as usual.

于 2010-10-24T07:44:37.610 に答える
1

From Python wiki

>>>import cgi
>>>cgi.escape("<string.h>")
>>>'&lt;string.h&gt;'

>>>BeautifulSoup('&lt;string.h&gt;', 
...               convertEntities=BeautifulSoup.HTML_ENTITIES)
于 2010-10-24T07:50:59.343 に答える
0

<code>要素にエスケープされていない<、、文字がコード内&に含まれている場合>、それは有効なhtmlではありません。BeautifulSoup有効なhtmlに変換しようとします。それはおそらくあなたが望むものではありません。

テキストを有効なhtmlに変換するには、htmlからタグを削除する正規表現を適応させて、ブロックからテキストを抽出し、バージョン<code>に置き換えcgi.escape()ます。<code>ネストされたタグがない場合は正常に機能するはずです。その後、サニタイズされたhtmlをにフィードできますBeautifulSoup。

于 2011-10-06T23:44:48.033 に答える
0

Unfortunately, BeautifulSoup can not be blocked to parse the code blocks.

One solution to what you want to achieve is too

1) Remove the code blocks

soup = BeautifulSoup(unicode(content))
code_blocks = soup.findAll(u'code')
for block in code_blocks:
    block.replaceWith(u'<code class="removed"></code>')

2) Do the usual parsing to strip the non-allowed tags.

3) Re-insert the code blocks and re-generate the html.

stripped_code = stripped_soup.findAll(u"code", u"removed")
# re-insert pygment formatted code

I would have answered with some code, but I recently read a blog that does this elegantly.

于 2010-10-24T07:49:59.897 に答える
0

編集：

python-markdown2を使用して入力を処理し、ユーザーにコード領域をインデントさせます。

>>> print html
I like this article, but the third code example <em>could have been simpler</em>:

    #include <stdbool.h>
    #include <stdio.h>

    int main()
    {
        printf("Hello World\n");
    }

>>> import markdown2
>>> marked = markdown2.markdown(html)
>>> marked
u'<p>I like this article, but the third code example <em>could have been simpler</em>:</p>\n\n<pre><code>#include &lt;stdbool.h&gt;\n#include &lt;stdio.h&gt;\n\nint main()\n{\n    printf("Hello World\\n");\n}\n</code></pre>\n'
>>> print marked
<p>I like this article, but the third code example <em>could have been simpler</em>:</p>

<pre><code>#include &lt;stdbool.h&gt;
#include &lt;stdio.h&gt;

int main()
{
    printf("Hello World\n");
}
</code></pre>

BeautifulSoup でナビゲートして編集する必要がある場合は、以下の手順を実行してください。'<' と '>' を ('<' と '>' の代わりに) 再挿入する必要がある場合は、エンティティ変換を含めます。

soup = BeautifulSoup(marked, 
                     convertEntities=BeautifulSoup.HTML_ENTITIES)
>>> soup
<p>I like this article, but the third code example <em>could have been simpler</em>:</p>
<pre><code>#include <stdbool.h>
#include <stdio.h>

int main()
{
    printf("Hello World\n");
}
</code></pre>


def thickened(soup):
    """
    <code>
    blah blah <entity> blah
        blah
    </code>
    """
    codez = soup.findAll('code') # get the code tags
    for code in codez:
        # take all the contents inside of the code tags and convert
        # them into a single string
        escape_me = ''.join([k.__str__() for k in code.contents])
        escaped = cgi.escape(escape_me) # escape them with cgi
        code.replaceWith('<code>%s</code>' % escaped) # replace Tag objects with escaped string
    return soup
于 2011-10-06T21:14:29.020 に答える