b のキーが a にあるかどうかを確認するには、辞書 b と a を比較する必要があります。交差するキーを見つけて、それらの値を確認します。
a = {'key_1': 1,'key_2': 2, 'key_3': 3}
b = {'key_1': 1,'key_2': 5}
# find keys common to both
inter = a.keys() & b
diff_vals = [(k, a[k], b[k]) for k in inter if a[k] != b[k]]
# find keys common to both
inter = a.keys() & b
for k,av, bv in diff_vals:
print("key = {}, val_a = {}, val_b = {}".format(k, av, bv))
key = key_2, val_a = 2, val_b = 5
dict_view objetcs でさまざまな set メソッドを使用できます。
# find key/value pairings that are unique to either dict
symmetric = a.items() ^ b.items()
{('key_2', 2), ('key_2', 5), ('key_3', 3)}
# key/values in b that are not in a
difference = b.items() - a.items()
{('key_2', 5)}
# key/values in a that are not in b
difference = a.items() - b.items()
{('key_3', 3), ('key_2', 2)}
# get unique set of all keys from a and b
union = a.keys() | b
{'key_1', 'key_2', 'key_3'}
# get keys common to both dicts
inter = a.keys() & b
{'key_1', 'key_2'}