データベース内のすべてのテーブルのすべてのインデックスを一覧表示 する最も簡単な方法は何だろうと思っています。
各テーブルを呼び出しsp_helpindexて結果を一時テーブルに保存する必要がありますか、それとももっと簡単な方法がありますか?
制約が sysobjects に格納されているのにインデックスが格納されていない理由を誰か説明できますか?
Lisa
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68405 次
6 に答える
37
必要なクエリの例を次に示します。
select
i.name as IndexName,
o.name as TableName,
ic.key_ordinal as ColumnOrder,
ic.is_included_column as IsIncluded,
co.[name] as ColumnName
from sys.indexes i
join sys.objects o on i.object_id = o.object_id
join sys.index_columns ic on ic.object_id = i.object_id
and ic.index_id = i.index_id
join sys.columns co on co.object_id = i.object_id
and co.column_id = ic.column_id
where i.[type] = 2
and i.is_unique = 0
and i.is_primary_key = 0
and o.[type] = 'U'
--and ic.is_included_column = 0
order by o.[name], i.[name], ic.is_included_column, ic.key_ordinal
;
これは、特定の目的に特化したものです (小さな C# アプリで使用して、重複するインデックスを見つけ、出力をフォーマットして、人間が実際に読めるようにします)。ただし、ニーズに合わせて簡単に調整できます。
于 2009-01-09T14:30:57.397 に答える
7
sysindexesを参照できます
もう 1 つの方法は、sp_helpindex のテキストを調べて、基になるテーブルから情報がどのように再構築されるかを確認することです。
sp_helptext 'sp_helpindex'
これについての参照はありませんが、制約は別の種類のものであるため、sysobjects には格納されないと思います。sysindexes には、sysobjects 内のオブジェクトに関するメタデータが含まれています。
于 2009-01-08T19:13:08.287 に答える
5
さらに詳しい情報が必要な場合は、私が時々使用する便利な SQL スクリプトを次に示します。
DECLARE @TabName varchar(100)
CREATE TABLE #temp (
TabName varchar(200), IndexName varchar(200), IndexDescr varchar(200),
IndexKeys varchar(200), IndexSize int
)
DECLARE cur CURSOR FAST_FORWARD LOCAL FOR
SELECT name FROM sysobjects WHERE xtype = 'U'
OPEN cur
FETCH NEXT FROM cur INTO @TabName
WHILE @@FETCH_STATUS = 0
BEGIN
INSERT INTO #temp (IndexName, IndexDescr, IndexKeys)
EXEC sp_helpindex @TabName
UPDATE #temp SET TabName = @TabName WHERE TabName IS NULL
FETCH NEXT FROM cur INTO @TabName
END
CLOSE cur
DEALLOCATE cur
DECLARE @ValueCoef int
SELECT @ValueCoef = low FROM Master.dbo.spt_values WHERE number = 1 AND type = N'E'
UPDATE #temp SET IndexSize =
((CAST(sysindexes.used AS bigint) * @ValueCoef)/1024)/1024
FROM sysobjects INNER JOIN sysindexes ON sysobjects.id = sysindexes.id
INNER JOIN #temp T ON T.TabName = sysobjects.name AND T.IndexName = sysindexes.name
SELECT * FROM #temp
ORDER BY TabName, IndexName
DROP TABLE #temp
于 2009-01-08T19:22:41.903 に答える
3
データベース内のすべてのインデックスを再作成する SQL ステートメントを返すスクリプトを次に示します。
SELECT ' CREATE ' +
CASE
WHEN I.is_unique = 1 THEN ' UNIQUE '
ELSE ''
END +
I.type_desc COLLATE DATABASE_DEFAULT + ' INDEX ' +
I.name + ' ON ' +
SCHEMA_NAME(T.schema_id) + '.' + T.name + ' ( ' +
KeyColumns + ' ) ' +
ISNULL(' INCLUDE (' + IncludedColumns + ' ) ', '') +
ISNULL(' WHERE ' + I.filter_definition, '') + ' WITH ( ' +
CASE
WHEN I.is_padded = 1 THEN ' PAD_INDEX = ON '
ELSE ' PAD_INDEX = OFF '
END + ',' +
'FILLFACTOR = ' + CONVERT(
CHAR(5),
CASE
WHEN I.fill_factor = 0 THEN 100
ELSE I.fill_factor
END
) + ',' +
-- default value
'SORT_IN_TEMPDB = OFF ' + ',' +
CASE
WHEN I.ignore_dup_key = 1 THEN ' IGNORE_DUP_KEY = ON '
ELSE ' IGNORE_DUP_KEY = OFF '
END + ',' +
CASE
WHEN ST.no_recompute = 0 THEN ' STATISTICS_NORECOMPUTE = OFF '
ELSE ' STATISTICS_NORECOMPUTE = ON '
END + ',' +
' ONLINE = OFF ' + ',' +
CASE
WHEN I.allow_row_locks = 1 THEN ' ALLOW_ROW_LOCKS = ON '
ELSE ' ALLOW_ROW_LOCKS = OFF '
END + ',' +
CASE
WHEN I.allow_page_locks = 1 THEN ' ALLOW_PAGE_LOCKS = ON '
ELSE ' ALLOW_PAGE_LOCKS = OFF '
END + ' ) ON [' +
DS.name + ' ] ' + CHAR(13) + CHAR(10) + ' GO' [CreateIndexScript]
FROM sys.indexes I
JOIN sys.tables T
ON T.object_id = I.object_id
JOIN sys.sysindexes SI
ON I.object_id = SI.id
AND I.index_id = SI.indid
JOIN (
SELECT *
FROM (
SELECT IC2.object_id,
IC2.index_id,
STUFF(
(
SELECT ' , ' + C.name + CASE
WHEN MAX(CONVERT(INT, IC1.is_descending_key))
= 1 THEN
' DESC '
ELSE
' ASC '
END
FROM sys.index_columns IC1
JOIN sys.columns C
ON C.object_id = IC1.object_id
AND C.column_id = IC1.column_id
AND IC1.is_included_column =
0
WHERE IC1.object_id = IC2.object_id
AND IC1.index_id = IC2.index_id
GROUP BY
IC1.object_id,
C.name,
index_id
ORDER BY
MAX(IC1.key_ordinal)
FOR XML PATH('')
),
1,
2,
''
) KeyColumns
FROM sys.index_columns IC2
--WHERE IC2.Object_id = object_id('Person.Address') --Comment for all tables
GROUP BY
IC2.object_id,
IC2.index_id
) tmp3
)tmp4
ON I.object_id = tmp4.object_id
AND I.Index_id = tmp4.index_id
JOIN sys.stats ST
ON ST.object_id = I.object_id
AND ST.stats_id = I.index_id
JOIN sys.data_spaces DS
ON I.data_space_id = DS.data_space_id
JOIN sys.filegroups FG
ON I.data_space_id = FG.data_space_id
LEFT JOIN (
SELECT *
FROM (
SELECT IC2.object_id,
IC2.index_id,
STUFF(
(
SELECT ' , ' + C.name
FROM sys.index_columns IC1
JOIN sys.columns C
ON C.object_id = IC1.object_id
AND C.column_id = IC1.column_id
AND IC1.is_included_column =
1
WHERE IC1.object_id = IC2.object_id
AND IC1.index_id = IC2.index_id
GROUP BY
IC1.object_id,
C.name,
index_id
FOR XML PATH('')
),
1,
2,
''
) IncludedColumns
FROM sys.index_columns IC2
--WHERE IC2.Object_id = object_id('Person.Address') --Comment for all tables
GROUP BY
IC2.object_id,
IC2.index_id
) tmp1
WHERE IncludedColumns IS NOT NULL
) tmp2
ON tmp2.object_id = I.object_id
AND tmp2.index_id = I.index_id
WHERE I.is_primary_key = 0
AND I.is_unique_constraint = 0
--AND T.name NOT LIKE 'mt_%'
--AND I.name NOT LIKE 'mt_%'
--AND I.Object_id = object_id('Person.Address') --Comment for all tables
--AND I.name = 'IX_Address_PostalCode' --comment for all indexes
于 2014-02-21T18:48:23.043 に答える