sql - 連続した時間間隔による SQL 結果のグループ化 (oracle sql)

Question

こんにちは、テーブルに次のデータがあります。

ID-----startDate----endDate
5549 2008-05-01 4712-12-31
5567 2008-04-17 2008-04-30 1
5567 2008-05-01 2008-07-31 1
5567 2008- 09-01 4712-12-31 2
5569 2008-05-01 2008-08-31
5569 2008-09-01 4712-12-31
5589 2008-04-18 2008-04-30
5589 2008-05-01 4712- 12-31
5667 2008-05-01 4712-12-31
5828 2008-06-03 4712-12-31
5867 2008-06-03 4712-12-31
6167 2008-11-01 4712-12-31
6207 2008- 07-01 4712-12-31
6228 2008-07-01 4712-12-31
6267 2008-07-14 4712-12-31

各IDが返す連続時間間隔をグループ化する方法を探しています:

ID、min(開始日)、max(終了日)、

太字の ID 5567 の結果としてこのような結果が得られます

5567 2008-04-17 2008-07-31
5567 2008-09-01 4712-12-31

ここではPL/SQLもオプションです:)

ありがとう、

Answer 1

私はこれがあなたが必要とすることをすると思います:(範囲が重複することでおそらく混乱することに注意してください;あなたのデータセットでそれらが可能かどうかはわかりません)

select id, min(start_date) period_start, max(end_date) period_end
from
(
select 
    id, start_date, end_date,
    max(contig) over (partition by id order by end_date) contiguous_group
from
(
select 
    id, start_date, end_date,
    case 
        when lag(end_date) over (partition by id order by end_date) != start_date-1 or row_number() over (partition by id order by end_date)=1 
            then row_number() over (partition by id order by end_date) else null end contig
from t2
)
)
group by id, contiguous_group
order by id, period_start
/

これが私が使用したテストデータです-いくつかの追加エントリを含むあなたのものに基づいています:

create table t2 (id number, start_date date, end_date date);

insert into t2(id, start_date, end_date)values(5549, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-04-17', 'yyyy-mm-dd'), to_date('2008-04-30', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('2008-07-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-08-01', 'yyyy-mm-dd'), to_date('2008-08-14', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2009-09-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-11-17', 'yyyy-mm-dd'), to_date('2008-12-13', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-12-14', 'yyyy-mm-dd'), to_date('2008-12-24', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5569, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('2008-08-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5569, to_date('2008-09-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5589, to_date('2008-04-18', 'yyyy-mm-dd'), to_date('2008-04-30', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5589, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5667, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5828, to_date('2008-06-03', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5867, to_date('2008-06-03', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6167, to_date('2008-11-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6207, to_date('2008-07-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6228, to_date('2008-07-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6267, to_date('2008-07-14', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));

commit;

Answer 2

これは、次のような分析関数で行うことができます。

with d as
( select id, start_date, end_date
  ,      case when start_date = prev_end+1 
              then 'cont' else 'new' end start_status
  ,      case when end_date = next_start-1
              then 'cont' else 'new' end end_stat
  from
  (
  select id, start_date, end_date
  ,      lag(end_date) over (partition by id order by start_date) prev_end
  ,      lead(start_date) over (partition by id order by start_date) next_start
  from t1
  order by id, start_date
  )
)
select starts.id, starts.start_date, ends.end_date
from
( select id, start_date, row_number() over (order by id, start_date) rn
  from   d
  where  start_status='new'
) starts,
( select id, end_date, row_number() over (order by id, start_date) rn
  from   d
  where  end_status='new'
) ends
where starts.rn = ends.rn

あなたのデータで次の結果が得られます。

        ID START_DATE END_DATE
---------- ---------- ----------
      5549 2008-05-01 4712-12-31
      5567 2008-04-17 2008-07-31
      5567 2008-09-01 4712-12-31
      5569 2008-05-01 4712-12-31
      5589 2008-04-18 4712-12-31
      5667 2008-05-01 4712-12-31
      5828 2008-06-03 4712-12-31
      5867 2008-06-03 4712-12-31
      6167 2008-11-01 4712-12-31
      6207 2008-07-01 4712-12-31
      6228 2008-07-01 4712-12-31
      6267 2008-07-14 4712-12-31

12 rows selected.

使い方：

1. WITH 句は、各行に「開始ステータス」と「終了ステータス」が割り当てられたデータのビュー D を生成します。それぞれのステータスは「新規」または「継続」で、前/次の行と連続しているかどうかを示します。か否か。
2. インラインビューの「開始」と「終了」は、それぞれ「新しい」開始ステータス/終了ステータスを持つ行のみを引き出し、それらを結びつける行番号を付けます。
3. 次に、「メイン クエリ」はこれら 2 つのビューから選択し、行番号列で結合します。

Answer 3

私はテストするインスタンスの近くにいませんが、試してみましたか?

SELECT
 ID, 
 startDate,
 endDate
FROM
 myTable
WHERE
 (ID, startDate) in 
 (SELECT
   ID, 
   min(startDate) 
  FROM
   myTable
  GROUP BY
   ID
  )

  or 

 (ID, endDate) in 
 (SELECT
   ID, 
   max(endDate) 
  FROM
   myTable
  GROUP BY
   ID
  )

これにより、ID ごとに最も古いstartDateと最新の がすべて表示されます。endDate継続的かどうか。

Answer 4

PL/SQL ブロックのサンプル ロジックを次のように記述する必要があります。

Create or Replace someproc
Declare
    Cursore someCur AS
    Select * from someTable
    Order by ID,StartDate

    IDVar as Varchar(10)
    MinDate as DATE
    MaxDate as DATE

Begin
    Open someCur
    Fetch ID,StartDate,EndDate into IDVar,MinDate,MaxDate
    While SomeCur%NOTFOUND
    LOOP
        Fetch ID,StartDate,EndDate into TempID,TempStartDate,TempEndDate
        if IDVar <> TempID then
            -- output into your required structure values: IDVar,MinDate,MaxDate
            IDVar = TempID
            MinDate = TempStartDate
            MaxDate = TempEndDate
            Exit Loop
        ELSE IF
            MaxDate+1 >= TempStartDate THEN
            MaxDate = TempEndDate
        END IF
    End LOOP

Answer 5

私は重複する範囲のためにやろうとしてきましたが、これらのデータでいくつかの困難を得ています:

     INSERT INTO zzz_scrap_dates (id,effdate,termdate)

SELECT id,effdate,termdate from (
SELECT '1'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2010-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('2005-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('1999-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
union
SELECT '2'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2010-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('2005-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('1999-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
union
SELECT '3'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('1998-01-01','YYYY-MM-DD')effdate,To_Date('1999-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('1005-01-01','YYYY-MM-DD')effdate,To_Date('1197-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('1197-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual