申し訳ありませんが、このトピックに再度投稿してください。これには 4 ページの結果があり、特定のソリューションに絞り込むのが難しくなっています。
この SQL の何が問題なのか誰にもわかりますか?
SELECT evntmst_id, count(evntmst_id) AS idcount
FROM evntcond
WHERE EVNTMST_ID NOT IN (
SELECT DISTINCT c.EVNTMST_ID
FROM evntcond c
LEFT JOIN evntmst m
ON c.EVNTMST_ID = m.EVNTMST_ID
WHERE m.EVNTMST_TYPE IN (1, 7) -- Group or Subset
AND m.EVNTMST_ID IS NOT NULL -- remove data integrity issues
GROUP BY c.EVNTMST_ID
ORDER BY c.EVNTMST_ID
)
GROUP BY EVNTMST_ID
ORDER BY count(evntmst_id) Desc
これにより、
ORA-00907: missing right parenthesis
入れ子になった SELECT DISTINCT を 1,2 に置き換えると、すべて正常に動作します。
SELECT evntmst_id, count(evntmst_id) AS idcount
FROM evntcond
WHERE EVNTMST_ID NOT IN (
1,2
)
GROUP BY EVNTMST_ID
ORDER BY count(evntmst_id) Desc
ネストされたクエリを独自に実行すると、すべて正常に動作します。
SELECT DISTINCT c.EVNTMST_ID
FROM evntcond c
LEFT JOIN evntmst m
ON c.EVNTMST_ID = m.EVNTMST_ID
WHERE m.EVNTMST_TYPE IN (1, 7) -- Group or Subset
AND m.EVNTMST_ID IS NOT NULL -- remove data integrity issues
GROUP BY c.EVNTMST_ID
ORDER BY c.EVNTMST_ID
オラクルとは何ですか。これはバグですか?