1 
SELECT 
     tbl_vehicle_models.model_name AS Vehicle_Model,
     tbl_vehicle_models.manufacturer AS Manufacturer,
     tbl_jobs.vehicle_registration_number AS Registration_Number,
     tbl_customers.first_name + " " + tbl_customers.last_name AS Customer_Name,
     tbl_customers.address AS Address,
     tbl_customers.contact_no AS Contact_Number,
     tbl_jobs.cost_charged AS Cost,
     tbl_jobs.was_accident AS Was_Accident,
     tbl_jobs.was_towed AS Was_Towed,
     tbl_jobs.job_call_time AS Call_Time,
     tbl_jobs.job_arrival_time AS Arrival_Time,
     tbl_jobs.job_leaving_scene_time AS Leaving_Time,
     tbl_places.place_name AS Place
FROM 
    tbl_jobs
    INNER JOIN  tbl_vehicle_models
       ON  ( tbl_vehicle_models.ID = tbl_jobs.vehicle_model ) 
    INNER JOIN tbl_customers
       ON ( tbl_customers.ID =  tbl_jobs.customer_id )
    INNER JOIN tbl_places
       ON ( tbl_places.ID = tbl_jobs.job_place )

このクエリの何が問題になっていますか? クエリ式 '( v.ID = j.vehicle_model ) INNER JOIN tbl_customers c ON ( c.id = j.customer_id ) INNER JOIN tbl_places p ON ( p.ID = j.job_place' に演算子がないというエラーが表示されます

編集:これは私の問題を解決しました:

SELECT tbl_vehicle_models.model_name, tbl_vehicle_models.manufacturer, tbl_jobs.vehicle_registration_number, tbl_customers.first_name & " " & tbl_customers.last_name AS Expr1, tbl_customers.address, tbl_customers.contact_no, tbl_jobs.cost_charged, tbl_jobs.was_accident, tbl_jobs.was_towed, tbl_jobs.job_call_time, tbl_jobs.job_arrival_time, tbl_jobs.job_leaving_scene_time, tbl_places.place_name
FROM ((tbl_jobs INNER JOIN tbl_vehicle_models ON tbl_jobs.vehicle_model = tbl_vehicle_models.ID) INNER JOIN tbl_customers ON tbl_jobs.customer_id = tbl_customers.ID) INNER JOIN tbl_places ON tbl_jobs.job_place = tbl_places.ID;
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2 に答える 2

0

これは私の問題を解決しました：

 SELECT tbl_vehicle_models.model_name, tbl_vehicle_models.manufacturer,
    tbl_jobs.vehicle_registration_number, tbl_customers.first_name & " " &
    tbl_customers.last_name AS Expr1, tbl_customers.address, tbl_customers.contact_no, 
    tbl_jobs.cost_charged, tbl_jobs.was_accident, tbl_jobs.was_towed, tbl_jobs.job_call_time,
    tbl_jobs.job_arrival_time, tbl_jobs.job_leaving_scene_time, tbl_places.place_name

    FROM ((tbl_jobs 
     INNER JOIN tbl_vehicle_models ON tbl_jobs.vehicle_model = tbl_vehicle_models.ID)
     INNER JOIN tbl_customers ON tbl_jobs.customer_id = tbl_customers.ID) 
     INNER JOIN tbl_places ON tbl_jobs.job_place = tbl_places.ID;
于 2011-04-26T05:32:19.123 に答える
0

同じデータ型を持っているv.IDと確信していますか?j.vehicle_model

v.ID整数とj.vehicle_model文字列のように見えます

この問題は、互換性のないオペランドのデータ型で演算子を使用しようとすると発生すると思います。

編集：次に、変更してみてください

c.first_name + " " + c.last_name

に

c.first_name & " " & c.last_name

それはこの連結の問題だと思います

于 2011-04-24T13:56:34.777 に答える