scala - uri で二重引用符と中括弧を使用する http4s

Question

解決策が見つかりません。この uri を作成する方法

import org.http4s._
import org.http4s.implicits.http4sLiteralsSyntax

val uriFoll: Uri = uri"https://www.instagram.com/graphql/query/?query_hash=c76146de99bb02f6415203be841dd25a&variables={"id":"374397360","include_reel":false,"fetch_mutual":false,"first":24}"

Answer 1

解決

val vars: String = "{\"id\":\"374397360\",\"include_reel\":false,\"fetch_mutual\":false,\"first\":24}"
val varsEncoded: String = Uri.encode(vars)
val uriFoll: Uri = Uri.unsafeFromString(s"https://www.instagram.com/graphql/query/?query_hash=c76146de99bb02f6415203be841dd25a&variables=$varsEncoded")