LinkedIn から へのリクエスト トークンをリクエストするとhttps://api.linkedin.com/uas/oauth/requestToken
、次のエラーが表示されます。
oauth_problem=signature_invalid&oauth_problem_advice=com.linkedin.security.auth.pub.LoginDeniedInvalidAuthTokenException%20while%20obtaining%20request%20token%20for%20%3APOST%26https%253A%252F%252Fapi.linkedin.com%252Fuas%252Foauth%252Frequest_Tokenback%26 253Doob%2526oauth_consumer_key%253DI9DvH3zT4c-sjmrQTmo_AeJOfi8v8n1ChYHYAV8A3siVLyu1qLZqPq_HiGecD0bp%2526oauth_nonce%253D2958724240022%2526oauth_signature_method%253DHMAC-SHA1%2526oauth_timestamp%253D1308562221%2526oauth_version%253D1.0%0AOAU%3AI9DvH3zT4c-sjmrQTmo_AeJOfi8v8n1ChYHYAV8A3siVLyu1qLZqPq_HiGecD0bp%7C%2A01%7C%2A01%7C%2A01%3A1308562221%3AkPisU0TwUgiNIYpigUrKITMwo7c% 3D
これは HTTP 401 Unauthorized 応答です。
例外:
net.oauth.exception.OAuthException: HTTP/1.0 401 Unauthorized
oauth_problem=signature_invalid&oauth_problem_advice=com.linkedin.security.auth.pub.LoginDeniedInvalidAuthTokenException%20while%20obtaining%20request%20token%20for%20%3APOST%26https%253A%252F%252Fapi.linkedin.com%252Fuas%252Foauth%252FrequestToken%26oauth_callback%253Doob%2526oauth_consumer_key%253DI9DvH3zT4c-sjmrQTmo_AeJOfi8v8n1ChYHYAV8A3siVLyu1qLZqPq_HiGecD0bp%2526oauth_nonce%253D2958724240022%2526oauth_signature_method%253DHMAC-SHA1%2526oauth_timestamp%253D1308562221%2526oauth_version%253D1.0%0AOAU%3AI9DvH3zT4c-sjmrQTmo_AeJOfi8v8n1ChYHYAV8A3siVLyu1qLZqPq_HiGecD0bp%7C%2A01%7C%2A01%7C%2A01%3A1308562221%3AkPisU0TwUgiNIYpigUrKITMwo7c%3D
at net.oauth.consumer.OAuth1Consumer.requestUnauthorizedToken(OAuth1Consumer.java:133)
at com.neurologic.example.LinkedInExample.requestUnauthorizedRequestToken(LinkedInExample.java:39)
at com.neurologic.example.LinkedInExample.main(LinkedInExample.java:57)
LinkedIn に接続するためのサンプル ソース コード:
/**
*
*/
package com.neurologic.example;
import net.oauth.consumer.OAuth1Consumer;
import net.oauth.exception.OAuthException;
import net.oauth.provider.OAuth1ServiceProvider;
import net.oauth.signature.impl.OAuthHmacSha1Signature;
import net.oauth.token.v1.AccessToken;
import net.oauth.token.v1.AuthorizedToken;
import net.oauth.token.v1.RequestToken;
/**
* @author Buhake Sindi
* @since 14 June 2011
*
*/
public class LinkedInExample {
private static final String LINKEDIN_API_URL = "https://api.linkedin.com";
private static final String API_KEY = "ENTER-API-KEY-HERE";
private static final String API_SECRET = "ENTER-API-SECRET-HERE";
private static final String CALLBACK_URL = "oob";
private OAuth1Consumer consumer;
/**
*
*/
public LinkedInExample() {
super();
// TODO Auto-generated constructor stub
consumer = new OAuth1Consumer(API_KEY, API_SECRET, new OAuth1ServiceProvider(LINKEDIN_API_URL + "/uas/oauth/requestToken", LINKEDIN_API_URL + "/uas/oauth/authorize", LINKEDIN_API_URL + "/uas/oauth/accessToken"));
}
public RequestToken requestUnauthorizedRequestToken() throws OAuthException {
return consumer.requestUnauthorizedToken(LINKEDIN_API_URL, CALLBACK_URL, null, new OAuthHmacSha1Signature());
}
public String getAuthorizationUrl(RequestToken token) throws OAuthException {
return consumer.createOAuthUserAuthorizationUrl(token, null);
}
public AccessToken requestAccessToken(AuthorizedToken authorizedToken, RequestToken requestToken) throws OAuthException {
return consumer.requestAccessToken(LINKEDIN_API_URL, requestToken, authorizedToken, new OAuthHmacSha1Signature());
}
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
LinkedInExample example = new LinkedInExample();
RequestToken rt = example.requestUnauthorizedRequestToken();
//Now that we have request token, let's authorize it....
String url = example.getAuthorizationUrl(rt);
//Copy the URL to your browser and make sure that OAuth 1 Servlet is running....
} catch (OAuthException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
私のライブラリ: JOAuth (バージョン 1.2.1)。com.linkedin.security.auth.pub.LoginDeniedInvalidAuthTokenException
LinkedIn からアドバイスを返す際に、私が何を間違えたのでしょうか?
ありがとう
PS: OAuth 1 は Twitter で完全に動作します (テスト済み)。そのため、何が起こっているのかわかりません。また、LinkedIn は JOAuth が準拠する OAuth 1.0 Revision A を使用します (RFC5849 と同様)。