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I have a ajax call to a php script that updates my MySQL DB with a new record when the user submits a data string as an entry. Part of the PHP is an if/else in place that will check to see if the entry is a duplicate. I can stop the duplicate from updating the database but I don't know how to send back an "error" message that says "That record already exists"...here is my jquery: [script] $(function() {

    $(".entry_button").click(function() 
{
    var element = $(this);
    var boxval = $("#entry").val();
    var dataString = 'entry='+ boxval;
        if(boxval=='') {
            alert("Please Enter Some Text");
        } else {

            $("#flash").show();
            $("#flash").fadeIn(400).html('<img src="images/loading.gif" align="absmiddle">&nbsp;<span class="loading">Broifying It...</span>');
            $.ajax({
                    type: "POST",
                    url: "update_data.php",
                    data: dataString,
                    cache: false,
                    success: function(html){
                        $("ol#update").prepend(html);
                        $("ol#update li").slideDown("slow");
                        document.getElementById('entry').value='';
                        $("#flash").hide();
                    }

            });
        }
        return false;
    });
});
[/script]

and here is my php script that updates the DB (update_data.php):

[php]
include('db.php');
if(isset($_POST['entry']))
{
$date_created = date('Y-m-d H:i:s');
$entry = $_POST['entry'];
$query = "SELECT COUNT(*) AS count FROM table WHERE entry = '$entry'";
$result = mysql_query($query);
$row = mysql_fetch_array($result);
if ($row['count'] == 0) {
mysql_query("insert into table (entry,date_created) values     ('$entry','$date_created')");
$sql_in= mysql_query("SELECT entry,id FROM table order by id desc");
$r=mysql_fetch_array($sql_in);
$newentry=$r['newentry'];
$id=$r['id'];
?>
<li class="entry bar<?php echo $id; ?>">
<div class="thebro"><span><?php echo $newentry; ?></span></div>
<div class="hr"></div>
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</li>
<?php
} else {
$error = "Sorry, that record already exists";
}   

}
[/php]

I want to be able to spit that $error variable from the php script to be sent back in the ajax call and be displayed in a element in my HTML. I've googled the crap out of ajax error messages but they all have to do with header errors, not validation error messages. I also am not using json_encode, unless someone wants to redo that jquery chunk above so that it is sent as json data.

Any ideas would be awesome!

4

3 に答える 3

0

それをphpfileにエコーして使用するだけです：

document.getElementById('ajaxCatchbox').innerHTML = ajaxRequest.responseText;

あなたのajaxrequestオブジェクトからの応答テキストは、エコーされたすべてのものを拾います... jquery thoで同等のものを知らない

于 2011-07-01T19:22:12.383 に答える
0

PHP でエラーをエコーし​​て終了します。次に、 success: 関数の開始時に、次のようにします。

    if(ajaxRequest.responseText.substring(0, 5) === 'Sorry') {
        alert(ajaxRequest.responseText);
        return;
    }

すべて「Sorry」で始まる限り、さまざまなエラー メッセージを作成できるため、サブストリング アプローチを使用することをお勧めします。デバッグに役立ちます。

于 2011-07-01T19:49:14.623 に答える