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I have a very simple voting form. It contains a single text field for entry ID, then five dropdowns. The only validation being done is on the text field, but if it fails, I want all of the dropdowns to keep their values.

For example, a user enters 12345 as the entry, then selects option A from all five dropdowns. (Option B is default.) If 12345 fails validation, the dropdowns should still be set to option A when the validation error is displayed. That’s not happening. I’m using the form helper’s form_dropdown to create the dropdowns. Any ideas? As you can see, I tried using set_value on the dropdown called q1, but it doesn’t work. The validation itself does work.

Here’s the code for the form:

<?php
$hidden = array('dot_judge_id' => $this->session->userdata('dot_judge_id'));

echo form_open('vote/create'); 
$entry_code_data = array(
    'name' => 'entry_code',
    'id' => 'entry_code',
    'value' => set_value('entry_code')
);

echo form_hidden($hidden);

$score_options = array('1'=>'1 (lowest)', '2'=>'2','3'=>'3', '4'=>'4','5'=>'5 (highest)');
?>

<p><label for="entry_code">Entry code: </label><?php echo form_input($entry_code_data); ?></p>
<p><label for="q1">Question 1: </label><?php echo form_dropdown('q1', $score_options, set_value('q1')); ?></p>
<p><label for="q2">Question 2: </label><?php echo form_dropdown('q2', $score_options, ''); ?></p>
<p><label for="q3">Question 3: </label><?php echo form_dropdown('q3', $score_options, ''); ?></p>
<p><label for="q4">Question 4: </label><?php echo form_dropdown('q4', $score_options, ''); ?></p>
<p><label for="q5">Question 5: </label><?php echo form_dropdown('q5', $score_options, ''); ?></p>

<p><?php echo form_submit('submit', 'Submit vote'); ?></p>                

<?php echo form_close(); ?>
<?php echo validation_errors('<p class="error">', '</p>');?>

I've had someone on the CodeIgniter forum tell me to use set_select, but I don’t think I can use set_select, because I’m not writing out the individual values of the select box, nor am I trying to provide a hard-coded default value. I need to reset the dropdowns to the values the user selected prior to running the form validation. I’m using the form_dropdown function, so how do I get the actual selected value to pass into the second param of set_select? According to the set_select documentation,

The first parameter must contain the name of the select menu, the second parameter must contain the value of each item

There was also a comment on this post that said to use set_value -echo form_dropdown('events', $options, set_value('events'), $firstItem);. The comment got three votes, so I'm assuming that it works for some people, but doesn't do anything for me. That question was a year old; perhaps that worked in an older version of CI but not the newest one. In any case, there HAS to be a way to have "sticky" dropdown values when creating dropdowns using form_dropdown, doesn't there? I can't imagine that I'd have to do it the long way and create the dropdown by looping through an array of values and echoing out each option line separately; that kind of defeats the purpose of using something like CI in the first place.

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2 に答える 2

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Remember that set_value() requires a second parameter that is the value of each item, so you can get this to work by adding $this->input->post('q1') as the second parameter.

Instead of:

<?php echo form_dropdown('q1', $score_options, set_value('q1')); ?>

You would write:

<?php echo form_dropdown('q1', $score_options, set_value('q1', $this->input->post('q1'))); ?>

Hope that helps.

于 2011-07-13T15:28:59.193 に答える
0

much easier,

   <select name="add_fields_type" id="add_fields_type">
     <option value="">Please Select</option>
     <option value="Input">Input</option>
     <option value="Text Area">Text Area</option>
     <option value="Radio Button">Radio Button</option>
     <option value="Check Box">Check Box</option>
   </select>


     <script>
      document.getElementById('select_status').value="<?php echo set_value('status'); ?>";
     </script>
于 2020-02-04T07:53:43.377 に答える