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Microsoft Access のパターン マッチングに metaphone アルゴリズムを使用したいと考えています。http://www.snakelegs.org/2008/01/18/double-metaphone-visual-basic-implementation/で 1 つのコードを見つけまし たが、動作せず、Microsoft Access 2007 がハングアップします。

私はsoundexを試しましたが、私の目的には十分ではありません。

どんな助けもかなりのものです...

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@Daredev、私はあなたの質問に直接答えることはできませんが、VBA/Accessの例を使ってあいまい検索に関するリソースに直接答えることはできます。残念ながら、それらはすべてドイツ語です。

どちらもサンプルデータベースと一緒にプレゼンテーションです。

于 2011-08-17T16:37:27.443 に答える
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以下がとても便利だと思いました。まず、Metaphone には 3 つのバージョンがあります -

  1. メタフォン
  2. ダブルメタフォン
  3. メタフォン V3

Metaphone のコードを以下に示します。ここで見つけたので、コードを少し編集しました。機能変更なし。

ここで、soundex の拡張バージョンもいくつか見つけました。

ダブルメタフォンをお探しの方はこちらをご覧ください。Visual Basic 内に COM ラッパーを提供し、データベース テーブル内の名前だけでなく、名前のリストを音声学的に検索します。

注:上記のアルゴリズムのどれがシナリオに適しているかコメントしてください。

メタフォン機能

Option Compare Database
Option Explicit

'Metaphone algorithm translated from C to Delphi by Tom White
'Translated to Visual Basic by Dave White 9/10/01
'
'v1.1 fixes a few bugs
'
' Checks length of string before removing trailing S (>1)
' PH used to translate to H, now translates to F

'Original C version by Michael Kuhn
'
'

主な機能はここから始まります

Function Metaphone(ByVal A As Variant) As String
Dim b, c, d, e As String
Dim inp, outp As String
Dim vowels, frontv, varson, dbl As String
Dim excppair, nxtltr As String
Dim T, ii, jj, lng, lastchr As Integer
Dim curltr, prevltr, nextltr, nextltr2, nextltr3 As String
Dim vowelafter, vowelbefore, frontvafter, silent, hard As Integer
Dim alphachr As String

On Error Resume Next
If IsNull(A) Then A = ""
A = CStr(A)
inp = UCase(A)
vowels = "AEIOU"
frontv = "EIY"
varson = "CSPTG"
dbl = "." 'Lets us allow certain letters to be doubled
excppair = "AGKPW"
nxtltr = "ENNNR"
alphachr = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"

'--Remove non-alpha characters
outp = ""
For T = 1 To Len(inp)
If InStr(alphachr, Mid(inp, T, 1)) > 0 Then outp = outp + Mid(inp, T, 1)
Next T

inp = outp: outp = ""

If Len(inp) = 0 Then Metaphone = "": Exit Function

'--Check rules at beginning of word
If Len(inp) > 1 Then
b = Mid(inp, 1, 1)
c = Mid(inp, 2, 1)
ii = InStr(excppair, b)
jj = InStr(nxtltr, c)
If ii = jj And ii > 0 Then
inp = Mid(inp, 2, Len(inp) - 1)
End If
End If

If Mid(inp, 1, 1) = "X" Then Mid(inp, 1, 1) = "S"

If Mid(inp, 1, 2) = "WH" Then inp = "W" + Mid(inp, 3)

If Right(inp, 1) = "S" Then inp = Left(inp, Len(inp) - 1)

ii = 0
Do
ii = ii + 1
'--Main Loop!
silent = False
hard = False
curltr = Mid(inp, ii, 1)
vowelbefore = False
prevltr = " "
If ii > 1 Then
prevltr = Mid(inp, ii - 1, 1)
If InStrC(prevltr, vowels) > 0 Then vowelbefore = True
End If

If ((ii = 1) And (InStrC(curltr, vowels) > 0)) Then
outp = outp + curltr
GoTo ContinueMainLoop
End If

vowelafter = False
frontvafter = False
nextltr = " "
If ii < Len(inp) Then
nextltr = Mid(inp, ii + 1, 1)
If InStrC(nextltr, vowels) > 0 Then vowelafter = True
If InStrC(nextltr, frontv) > 0 Then frontvafter = True
End If

'--Skip double letters EXCEPT ones in variable double
If InStrC(curltr, dbl) = 0 Then
If curltr = nextltr Then GoTo ContinueMainLoop
End If

nextltr2 = " "
If Len(inp) - ii > 1 Then
nextltr2 = Mid(inp, ii + 2, 1)
End If

nextltr3 = " "
If (Len(inp) - ii) > 2 Then
nextltr3 = Mid(inp, ii + 3, 1)
End If

Select Case curltr
Case "B":
silent = False
If (ii = Len(inp)) And (prevltr = "M") Then silent = True
If Not (silent) Then outp = outp + curltr
Case "C":
If Not ((ii > 2) And (prevltr = "S") And frontvafter) Then
If ((ii > 1) And (nextltr = "I") And (nextltr2 = "A")) Then
outp = outp + "X"
Else
If frontvafter Then
outp = outp + "S"
Else
If ((ii > 2) And (prevltr = "S") And (nextltr = "H")) Then
outp = outp + "K"
Else
If nextltr = "H" Then
If ((ii = 1) And (InStrC(nextltr2, vowels) = 0)) Then
outp = outp + "K"
Else
outp = outp + "X"
End If
Else
If prevltr = "C" Then
outp = outp + "C"
Else
outp = outp + "K"
End If
End If
End If
End If
End If
End If
Case "D":
If ((nextltr = "G") And (InStrC(nextltr2, frontv) > 0)) Then
outp = outp + "J"
Else
outp = outp + "T"
End If

Case "G":
silent = False
If ((ii < Len(inp)) And (nextltr = "H") And (InStrC(nextltr2, vowels) = 0)) Then
silent = True
End If
If ((ii = Len(inp) - 4) And (nextltr = "N") And (nextltr2 = "E") And (nextltr3 = "D")) Then
silent = True
ElseIf ((ii = Len(inp) - 2) And (nextltr = "N")) Then
silent = True
End If
If (prevltr = "D") And frontvafter Then silent = True
If prevltr = "G" Then
hard = True
End If

If Not (silent) Then
If frontvafter And (Not (hard)) Then
outp = outp + "J"
Else
outp = outp + "K"
End If
End If

Case "H":
silent = False
If InStrC(prevltr, varson) > 0 Then silent = True
If vowelbefore And (Not (vowelafter)) Then silent = True
If Not silent Then outp = outp + curltr

Case "F", "J", "L", "M", "N", "R": outp = outp + curltr

Case "K": If prevltr <> "C" Then outp = outp + curltr

Case "P": If nextltr = "H" Then outp = outp + "F" Else outp = outp + "P"

Case "Q": outp = outp + "K"

Case "S":
If ((ii > 2) And (nextltr = "I") And ((nextltr2 = "O") Or (nextltr2 = "A"))) Then
outp = outp + "X"
End If
If (nextltr = "H") Then
outp = outp + "X"
Else
outp = outp + "S"
End If

Case "T":
If ((ii > 0) And (nextltr = "I") And ((nextltr2 = "O") Or (nextltr2 = "A"))) Then
outp = outp + "X"
End If
If nextltr = "H" Then
If ((ii > 1) Or (InStrC(nextltr2, vowels) > 0)) Then
outp = outp + "0"
Else
outp = outp + "T"
End If
ElseIf Not ((ii < Len(inp) - 3) And (nextltr = "C") And (nextltr2 = "H")) Then
outp = outp + "T"
End If

Case "V": outp = outp + "F"

Case "W", "Y": If (ii < Len(inp) - 1) And vowelafter Then outp = outp + curltr

Case "X": outp = outp + "KS"

Case "Z": outp = outp + "S"

End Select
ContinueMainLoop:
Loop Until (ii > Len(inp))

Metaphone = outp

End Function

これも必要

Function InStrC(ByVal SearchIn As String, ByVal SoughtCharacters As String) As Integer
'--- Returns the position of the first character in SearchIn that is contained
'--- in the string SoughtCharacters. Returns 0 if none found.
Dim i As Integer

On Error Resume Next
SoughtCharacters = UCase(SoughtCharacters)
SearchIn = UCase(SearchIn)
For i = 1 To Len(SearchIn)
If InStr(SoughtCharacters, Mid(SearchIn, i, 1)) > 0 Then
InStrC = i: Exit Function
End If
Next i
InStrC = 0
End Function
于 2016-03-01T20:35:44.693 に答える