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WCFストリーミングファイル転送の良い例が必要です。

いくつか見つけて試しましたが、投稿が古く、.net4とIIS7で問題が発生しているため、いくつかの問題があります。

その上で最新の良い例を教えてください。

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1 に答える 1

7

以下の回答は、RESTfulサービスにバイナリデータを投稿するためのいくつかの手法を使用して詳しく説明しています。

次のコードは、RESTful WCFサービスを作成する方法のサンプルであり、完全ではありませんが、どこから開始できるかを示しています。

サンプルサービス。これは本番環境に対応したコードではないことに注意してください。

[ServiceContract]
[AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)]
[ServiceBehavior(InstanceContextMode = InstanceContextMode.PerCall)]
public class FileService
{
    private IncomingWebRequestContext m_Request;
    private OutgoingWebResponseContext m_Response;

    [WebGet(UriTemplate = "{appName}/{id}?action={action}")]
    public Stream GetFile(string appName, string id, string action)
    {
        var repository = new FileRepository();
        var response = WebOperationContext.Current.OutgoingResponse;
        var result = repository.GetById(int.Parse(id));

        if (action != null && action.Equals("download", StringComparison.InvariantCultureIgnoreCase))
        {
            response.Headers.Add("Content-Disposition", string.Format("attachment; filename={0}", result.Name));
        }

        response.Headers.Add(HttpResponseHeader.ContentType, result.ContentType);
        response.Headers.Add("X-Filename", result.Name);

        return result.Content;
    }

    [WebInvoke(UriTemplate = "{appName}", Method = "POST")]
    public void Save(string appName, Stream fileContent)
    {
        try
        {
            if (WebOperationContext.Current == null) throw new InvalidOperationException("WebOperationContext is null.");

            m_Request = WebOperationContext.Current.IncomingRequest;
            m_Response = WebOperationContext.Current.OutgoingResponse;

            var file = CreateFileResource(fileContent, appName);

            if (!FileIsValid(file)) throw new WebFaultException(HttpStatusCode.BadRequest);

            SaveFile(file);

            SetStatusAsCreated(file);
        }
        catch (Exception ex)
        {
            if (ex.GetType() == typeof(WebFaultException)) throw;
            if (ex.GetType().IsGenericType && ex.GetType().GetGenericTypeDefinition() == typeof(WebFaultException<>)) throw;

            throw new WebFaultException<string>("An unexpected error occurred.", HttpStatusCode.InternalServerError);
        }
    }

    private FileResource CreateFileResource(Stream fileContent, string appName)
    {
        var result = new FileResource();

        fileContent.CopyTo(result.Content);
        result.ApplicationName = appName;
        result.Name = m_Request.Headers["X-Filename"];
        result.Location = @"C:\SomeFolder\" + result.Name;
        result.ContentType = m_Request.Headers[HttpRequestHeader.ContentType] ?? this.GetContentType(result.Name);
        result.DateUploaded = DateTime.Now;

        return result;
    }

    private string GetContentType(string filename)
    {
        // this should be replaced with some form of logic to determine the correct file content type (I.E., use registry, extension, xml file, etc.,)
        return "application/octet-stream";
    }

    private bool FileIsValid(FileResource file)
    {
        var validator = new FileResourceValidator();
        var clientHash = m_Request.Headers[HttpRequestHeader.ContentMd5];

        return validator.IsValid(file, clientHash);
    }

    private void SaveFile(FileResource file)
    {
        // This will persist the meta data about the file to a database (I.E., size, filename, file location, etc)
        new FileRepository().AddFile(file);
    }

    private void SetStatusAsCreated(FileResource file)
    {
        var location = new Uri(m_Request.UriTemplateMatch.RequestUri.AbsoluteUri + "/" + file.Id);
        m_Response.SetStatusAsCreated(location);
    }
}

サンプルクライアント、これは本番環境に対応したコードではないことに注意してください。

// *********************************
// Sample Client
// *********************************
private void UploadButton_Click(object sender, EventArgs e)
{
    var uri = "http://dev-fileservice/SampleApplication"
    var fullFilename = @"C:\somefile.txt";
    var fileContent = File.ReadAllBytes(fullFilename);

    using (var webClient = new WebClient())
    {
        try
        {
            webClient.Proxy = null;
            webClient.Headers.Add(HttpRequestHeader.ContentMd5, this.CalculateFileHash());
            webClient.Headers.Add("X-DaysToKeep", DurationNumericUpDown.Value.ToString());
            webClient.Headers.Add("X-Filename", Path.GetFileName(fullFilename));
            webClient.UploadData(uri, "POST", fileContent);

            var fileUri = webClient.ResponseHeaders[HttpResponseHeader.Location];
            Console.WriteLine("File can be downloaded at" + fileUri);
        }
        catch (Exception ex)
        {
            var exception = ex.Message;
        }
    }
}

private string CalculateFileHash()
{
    var hash = MD5.Create().ComputeHash(File.ReadAllBytes(@"C:\somefile.txt"));
    var sb = new StringBuilder();

    for (int i = 0; i < hash.Length; i++)
    {
        sb.Append(hash[i].ToString("x2"));
    }

    return sb.ToString();
}

private void DownloadFile()
{
    var uri = "http://dev-fileservice/SampleApplication/1" // this is the URL returned by the Restful file service

    using (var webClient = new WebClient())
    {
        try
        {
            webClient.Proxy = null;
            var fileContent = webClient.DownloadData(uri);
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
    }
}
于 2011-07-28T12:05:07.057 に答える