5

Oracle PIVOT 句でユーザー定義の集計関数を使用できません。

string_agg というユーザー定義の集計関数を作成しました。
などの簡単な文で使用できます... 

select id, string_agg(value) from
(
    select 'user1' as id, 'BMW' as value,   'CAR'      as type from dual    union
    select 'user1' as id, 'Audi' as value,  'CAR'      as type from dual    union
    select 'user2' as id, 'Honda' as value, 'CAR'      as type from dual    union
    select 'user1' as id, 'Dell' as value,  'COMPUTER' as type from dual    union
    select 'user1' as id, 'Sony' as value,  'COMPUTER' as type from dual    union
    select 'user2' as id, 'HP' as value,    'COMPUTER' as type from dual 
)
group by id, type

結果: 
ID          TYPE            STRING_AGG(VALUE)
user1       CAR             Audi,BMW
user1       COMPUTER        Dell,Sony
user2       CAR             Honda
user2       COMPUTER        HP

ただし、ピボット句で同じ関数を使用しようとすると
select * from
( 
    select id, type, string_agg(value) as value from
    (
        select 'user1' as id, 'BMW' as value,   'CAR'      as type from dual    union
        select 'user1' as id, 'Audi' as value,  'CAR'      as type from dual    union
        select 'user2' as id, 'Honda' as value, 'CAR'      as type from dual    union
        select 'user1' as id, 'Dell' as value,  'COMPUTER' as type from dual    union
        select 'user1' as id, 'Sony' as value,  'COMPUTER' as type from dual    union
        select 'user2' as id, 'HP' as value,    'COMPUTER' as type from dual 
    )
    group by id, type
)
PIVOT (string_agg(value) FOR id IN ('user1' user1, 'user2' user2) );

次のエラーが表示されます... 
ORA-56902: expect aggregate function inside pivot operation

期待される結果は...

TYPE        USER1       USER2
COMPUTER    Dell,Sony   HP       
CAR         Audi,BMW    Honda
4

2 に答える 2

0

ピボットは同じ集計関数である必要はありません:

select * from
( 
    select id, type, LISTAGG(value) WITHIN GROUP (ORDER BY 1) as value from
    (
        select 'user1' as id, 'BMW' as value,   'CAR'      as type from dual    union
        select 'user1' as id, 'Audi' as value,  'CAR'      as type from dual    union
        select 'user2' as id, 'Honda' as value, 'CAR'      as type from dual    union
        select 'user1' as id, 'Dell' as value,  'COMPUTER' as type from dual    union
        select 'user1' as id, 'Sony' as value,  'COMPUTER' as type from dual    union
        select 'user2' as id, 'HP' as value,    'COMPUTER' as type from dual 
    )
    group by id, type
)
PIVOT (max(value) FOR id IN ('user1' user1, 'user2' user2) );
于 2011-08-03T23:10:02.467 に答える