assembly - コードがベクトル化されているかどうかを確認するにはどうすればよいですか？

Question

I am using Automatic Vectorization of compiler to generate the vectorized Code.
For. e.g.  
    for (i = 0; i < 20; i++)  
    {  
        A[i] = i;  
    }  
    for (i = 0; i < 20; i++)  
    {  
        A[i] = A[i] + 5;  
    }

For the above code I am getting assembly code as below ? Is it vectorized or not ?
-------------------------------------------------------------------  
8048380:    55                      push   %ebp  
 8048381:   89 e5                   mov    %esp,%ebp  
 8048383:   56                      push   %esi  
 8048384:   83 ec 64                sub    $0x64,%esp  
 8048387:   c7 45 ac 05 00 00 00    movl   $0x5,-0x54(%ebp)  
 804838e:   c7 45 b0 06 00 00 00    movl   $0x6,-0x50(%ebp)  
 8048395:   c7 45 b4 07 00 00 00    movl   $0x7,-0x4c(%ebp)  
 804839c:   c7 45 b8 08 00 00 00    movl   $0x8,-0x48(%ebp)  
 80483a3:   c7 45 bc 09 00 00 00    movl   $0x9,-0x44(%ebp)  
 80483aa:   c7 45 c0 0a 00 00 00    movl   $0xa,-0x40(%ebp)  
 80483b1:   c7 45 c4 0b 00 00 00    movl   $0xb,-0x3c(%ebp)  
 80483b8:   c7 45 c8 0c 00 00 00    movl   $0xc,-0x38(%ebp)  
 80483bf:   c7 45 cc 0d 00 00 00    movl   $0xd,-0x34(%ebp)  
 80483c6:   c7 45 d0 0e 00 00 00    movl   $0xe,-0x30(%ebp)  
 80483cd:   c7 45 d4 0f 00 00 00    movl   $0xf,-0x2c(%ebp)  
 80483d4:   c7 45 d8 10 00 00 00    movl   $0x10,-0x28(%ebp)  
 80483db:   c7 45 dc 11 00 00 00    movl   $0x11,-0x24(%ebp)  
 80483e2:   c7 45 e0 12 00 00 00    movl   $0x12,-0x20(%ebp)  
 80483e9:   c7 45 e4 13 00 00 00    movl   $0x13,-0x1c(%ebp)  
 80483f0:   c7 45 e8 14 00 00 00    movl   $0x14,-0x18(%ebp)  
 80483f7:   c7 45 ec 15 00 00 00    movl   $0x15,-0x14(%ebp)  
 80483fe:   c7 45 f0 16 00 00 00    movl   $0x16,-0x10(%ebp)  
 8048405:   c7 45 f4 17 00 00 00    movl   $0x17,-0xc(%ebp)  
 804840c:   c7 45 f8 18 00 00 00    movl   $0x18,-0x8(%ebp)  
-----------------------------------------------------------------------  

Answer 1

ベクトル化されていません。

ただし、展開され、最初のループが削除されます。