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I have timestamps in a column which I have imported in SPSS. Example, 7/6/2011 2:21 in a column called 'Observation'

This is in the string format. Now I also have timezone corrections for these data. So, -60 would mean subtract 60 minutes from this date.

How would I do this in SPSS syntax?

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SPSS にはネイティブの日付形式がありますが、残念ながら、投稿した例をカバーしているようには見えません。文字列フィールドの先頭を解析してmm/dd/yyyyと のhh:mm部分を分離し、それらを代表的な時間形式に変換してから、時間の計算を行います。

例として

data list fixed / observation (A25).
begin data
7/6/2011 2:21
10/11/2011 15:42
07/06/2011 02:21
3/15/2011 0:21
end data.

*getting the data part, assuming the space will always delimit the two parts.
compute #space = char.index(observation," ").
string date (A10).
compute date = char.substr(observation,1,#space-1).
*getting the time part.
string time (A5).
compute time = char.substr(observation,#space+1,5).
execute.

*now converting them into date formats.
alter type date (A10 = ADATE10).
alter type time (A5 = TIME5).
*you should check these carefully to make sure they were converted correctly.
*now making one time variable.
compute date_time = date + time.
formats date_time (DATETIME17).
execute.

*now it is just as simple as subtracting the specified value.
compute date_time_adj = DATESUM(date_time,-60,"minutes").
execute.
formats date_time_adj (DATETIME17).
于 2011-09-09T16:15:42.090 に答える