1

「日付」列のテーブルがあり、「2011-09-06」の形式で日付を入力し、クエリを実行したい：

select * from tvprograms where date=?

そして、私はこれを試します:

Date startDate;
java.util.Date date;
Calendar cal = Calendar.getInstance();
cal.set(2011, 9, 1);
startDate = cal.getTime();
TVProgramDAO tvDAO = new TVProgramDAO();
tvDAO.findUnusedTvPrograms(new java.sql.Date(date.getTime()));

findUnusedTvPrograms の外観:

public List<Integer> findUnusedTvPrograms(Date date) {
    List<Integer> results = new ArrayList<Integer>();
    if (obtainConnection()) {
        PreparedStatement stmt = null;
        ResultSet rs = null;
        ...
            stmt = con.prepareStatement(findOldTvProgQuery.toString());

            stmt.setDate(1, date);
            rs = stmt.executeQuery();

            while (rs.next()) {

                results.add(rs.getInt(1));
             ...
    return results;
}

しかし、うまくいきません。

4

1 に答える 1

2

This code won't compile to start with as far as I can see:

Date startDate;
java.util.Date date;
Calendar cal = Calendar.getInstance();
cal.set(2011, 9, 1);
startDate = cal.getTime();
TVProgramDAO tvDAO = new TVProgramDAO();
tvDAO.findUnusedTvPrograms(new java.sql.Date(date.getTime()));

You're trying to use date but you've never initialized the variable. Here's a slightly cleaner version:

Calendar cal = Calendar.getInstance();
cal.set(2011, 9, 1);
Date startDate = cal.getTime();
TVProgramDAO tvDAO = new TVProgramDAO();
tvDAO.findUnusedTvPrograms(new java.sql.Date(startDate.getTime()));

Note that that will use the default time zone of the system, which may not be a good idea. Personally I would recommend using Joda Time instead...

于 2011-09-13T14:26:01.373 に答える