2

次のクエリをLINQに変換する方法について頭を悩ませようと午後を過ごしましたが、そこにたどり着くことができません。

declare @productId int; set @productId = 3212;

select * from InformationData data where productId = @productId and orgId = 1
and exists(
    select id from (
        select coalesce(id1.id, id2.id, id3.id) as id from (
            select productId,attributeId from InformationData where productId = @productId group by productId,attributeId
        ) id
        left outer join InformationData id1 on id1.productId = id.productId and id1.attributeId = id.attributeId and id1.language = 1
        left outer join InformationData id2 on id2.productId = id.productId and id2.attributeId = id.attributeId and id2.language = 2
        left outer join InformationData id3 on id3.productId = id.productId and id3.attributeId = id.attributeId and id3.language = 0
    ) row
    where row.id = data.id
)

クエリの目的は、2つのフォールバック言語を使用してテーブルからデータをフェッチすることです。したがって、データが言語1に存在しない場合は、言語2でフェッチされ、2が存在しない場合は、言語0でフェッチされます。グローバル翻訳。

内部クエリをほぼ正しく取得できます（id1.language = 1を除いて、参加しているテーブルのメンバーに参加させることができないようです、何かアイデアはありますか？）

これは私のコード（LINQPadコード）です：

(
    from data in (
        from d in InformationData where d.ProductId == 3212 group d by new { d.ProductId, d.AttributeId } into p select new { ProductId = p.Key.ProductId, AttributeId = p.Key.AttributeId }
    )
    join x1 in InformationData on new { a = data.ProductId, b = data.AttributeId } equals new { a = x1.ProductId, b = x1.AttributeId } into f1
        from r1 in f1.DefaultIfEmpty()
        where r1.Language == 1
    join x2 in InformationData on new { a = data.ProductId, b = data.AttributeId } equals new { a = x2.ProductId, b = x2.AttributeId } into f2
        from r2 in f2.DefaultIfEmpty()
        where r2.Language == 2
    join x3 in InformationData on new { a = data.ProductId, b = data.AttributeId } equals new { a = x3.ProductId, b = x3.AttributeId } into f3
        from r3 in f3.DefaultIfEmpty()
        where r3.Language == 2
    select new { Id = ((int?)r1.Id) ?? ((int?)r2.Id) ?? r3.Id }
).Dump();

これにより、次のSQLが生成されます。

-- Region Parameters
DECLARE @p0 Int SET @p0 = 3212
DECLARE @p1 Int SET @p1 = 2
DECLARE @p2 Int SET @p2 = 2
DECLARE @p3 Int SET @p3 = 1
-- EndRegion
SELECT COALESCE([t2].[id],COALESCE([t3].[id],[t4].[id])) AS [Id]
FROM (
    SELECT [t0].[productId], [t0].[attributeId]
    FROM [InformationData] AS [t0]
    WHERE [t0].[productId] = @p0
    GROUP BY [t0].[productId], [t0].[attributeId]
    ) AS [t1]
LEFT OUTER JOIN [InformationData] AS [t2] ON ([t1].[productId] = [t2].[productId]) AND ([t1].[attributeId] = [t2].[attributeId])
LEFT OUTER JOIN [InformationData] AS [t3] ON ([t1].[productId] = [t3].[productId]) AND ([t1].[attributeId] = [t3].[attributeId])
LEFT OUTER JOIN [InformationData] AS [t4] ON ([t1].[productId] = [t4].[productId]) AND ([t1].[attributeId] = [t4].[attributeId])
WHERE ([t4].[language] = @p1) AND ([t3].[language] = @p2) AND ([t2].[language] = @p3)

しかし、これを残りのクエリと組み合わせることができません。たぶん、購入するのに疲れているだけで、多くのCROSSAPPLYを実行し続けています。誰か提案はありますか？

4

2 に答える 2

3

よく眠った後、いくつかの歯ごたえのあるものが少し明るくなり、私は解決策を見つけました:)ここに興味がある人にとっては


(
    from i in InformationData
    where (
        from data in (
            from d in InformationData where d.ProductId == 3212 group d by new { d.ProductId, d.AttributeId } into p select new { ProductId = p.Key.ProductId, AttributeId = p.Key.AttributeId }
        )
        join x1 in InformationData on new { a = data.ProductId, b = data.AttributeId, c = 1} equals new { a = x1.ProductId, b = x1.AttributeId, c = x1.Language } into f1
            from r1 in f1.DefaultIfEmpty()
        join x2 in InformationData on new { a = data.ProductId, b = data.AttributeId, c = 2 } equals new { a = x2.ProductId, b = x2.AttributeId, c = x2.Language } into f2
            from r2 in f2.DefaultIfEmpty()
        join x3 in InformationData on new { a = data.ProductId, b = data.AttributeId, c = 0 } equals new { a = x3.ProductId, b = x3.AttributeId, c = x3.Language } into f3
            from r3 in f3.DefaultIfEmpty()
        select new { Id = ((int?)r1.Id) ?? ((int?)r2.Id) ?? r3.Id }
    ).Any(d => d.Id == i.Id)
    select i
).Dump();

そしてこれが生成されたSQLです


-- Region Parameters
DECLARE @p0 Int SET @p0 = 3212
DECLARE @p1 Int SET @p1 = 1
DECLARE @p2 Int SET @p2 = 2
DECLARE @p3 Int SET @p3 = 0
-- EndRegion
SELECT [t0].[id] AS [Id], [t0].[attributeId] AS [AttributeId], [t0].[productId] AS [ProductId], [t0].[value] AS [Value], [t0].[orgId] AS [OrgId], [t0].[version] AS [Version], [t0].[language] AS [Language], [t0].[metaType] AS [MetaType], [t0].[overload] AS [Overload], [t0].[parentId] AS [ParentId]
FROM [InformationData] AS [t0]
WHERE EXISTS(
    SELECT NULL AS [EMPTY]
    FROM (
        SELECT COALESCE([t3].[id],COALESCE([t4].[id],[t5].[id])) AS [value]
        FROM (
            SELECT [t1].[productId], [t1].[attributeId]
            FROM [InformationData] AS [t1]
            WHERE [t1].[productId] = @p0
            GROUP BY [t1].[productId], [t1].[attributeId]
            ) AS [t2]
        LEFT OUTER JOIN [InformationData] AS [t3] ON ([t2].[productId] = [t3].[productId]) AND ([t2].[attributeId] = [t3].[attributeId]) AND (@p1 = [t3].[language])
        LEFT OUTER JOIN [InformationData] AS [t4] ON ([t2].[productId] = [t4].[productId]) AND ([t2].[attributeId] = [t4].[attributeId]) AND (@p2 = [t4].[language])
        LEFT OUTER JOIN [InformationData] AS [t5] ON ([t2].[productId] = [t5].[productId]) AND ([t2].[attributeId] = [t5].[attributeId]) AND (@p3 = [t5].[language])
        ) AS [t6]
    WHERE [t6].[value] = [t0].[id]
    )
于 2009-05-08T08:55:22.777 に答える
2

主にクエリの実行内容の説明に基づいて、適切な「orderby」句を使用して最初の結果だけを取得することで、同じ結果を達成できる可能性があると思います。このような：

var result =
(
    from d in InformationData
    where d.ProductId == 3212
    orderby ((d.language == 0) ? Int32.MaxValue : d.language)
    select d
).First();

編集：orderby句を拡張することにより、検索の優先順位を制御できます。たとえば、優先順位を2、3、1、その他の場合、次のように実行できます。

var result =
(
    from d in InformationData
    where d.ProductId == 3212
    orderby
        (d.language == 2) ? 0
        : (d.language == 3) ? 1
        : (d.language == 1) ? 2
        : Int32.MaxValue
    select d
).First();
于 2009-05-07T18:21:26.810 に答える