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会社のソフトウェアの仕様に取り組んでおり、監査システムの一部として、現在の Active Directory ユーザーを取得する方法があればいいと思います。

うまくいけば、次のようなものです：

Dim strUser as String
strUser = ActiveDirectory.User()
MsgBox "Welcome back, " & strUser
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4 に答える 4

6

この記事を試してみてください- 私は動作するコードをいくつか持っています。

関連する引用:

Private Declare Function GetUserName Lib "advapi32.dll" Alias "GetUserNameA" _
                    (ByVal IpBuffer As String, nSize As Long) As Long
Private Declare Function GetComputerName Lib "kernel32" Alias "GetComputerNameA" _
                    (ByVal lpBuffer As String, nSize As Long) As Long

Function ThisUserName() As String
    Dim LngBufLen As Long
    Dim strUser As String

    strUser = String$(15, " ")
    LngBufLen = 15

    If GetUserName(strUser, LngBufLen) = 1 Then
        ThisUserName = Left(strUser, LngBufLen - 1)
    Else
        ThisUserName = "Unknown"
    End If
End Function

Function ThisComputerID() As String
    Dim LngBufLen As Long
    Dim strUser As String

    strUser = String$(15, " ")
    LngBufLen = 15

    If GetComputerName(strUser, LngBufLen) = 1 Then
        ThisComputerID = Left(strUser, LngBufLen)
    Else
        ThisComputerID = 0
    End If
End Function
于 2008-08-12T17:07:52.563 に答える
4

ここに私のバージョンがあります:それはあなたが好きなものを取得します:

'gets firstname, lastname, fullname or username
Public Function GetUser(Optional whatpart = "username")
    Dim returnthis As String
    If whatpart = "username" Then GetUser = Environ("USERNAME"): Exit Function
    Set objSysInfo = CreateObject("ADSystemInfo")
    Set objUser = GetObject("LDAP://" & objSysInfo.USERNAME)
    Select Case whatpart
        Case "fullname": returnthis = objUser.FullName
        Case "firstname", "givenname": returnthis = objUser.givenName
        Case "lastname": returnthis = objUser.LastName
        Case Else: returnthis = Environ("USERNAME")
    End Select
    GetUser = returnthis
End Function

Spiceworks から元のアイデアを得ました。

于 2015-07-18T22:14:47.730 に答える
2

David は、環境変数を使用するリスクについて非常に良い指摘をしました。環境変数には他にも問題がある可能性があることを付け加えることしかできません。この 5 年前のプロジェクトの実際のコード フラグメントを見てください。

Public Function CurrentWorkbenchUser() As String

    ' 2004-01-05, YM: Using Application.CurrentUser for identification of 
    ' current user is very problematic (more specifically, extremely 
    ' cumbersome to set up and administer for all users). 
    ' Therefore, as a quick fix, let's use the OS-level user's 
    ' identity instead (NB: the environment variables used below must work fine
    ' on Windows NT/2000/2003 but may not work on Windows 98/ME)
    ' CurrentWorkbenchUser = Application.CurrentUser
    '
    ' 2005-06-13, YM: Environment variables do not work in Windows 2003. 
    ' Use Windows Scripting Host (WSH) Networking object instead.
    ' CurrentWorkbenchUser = Environ("UserDomain") & "\" & Environ("UserName")
    '
    ' 2007-01-23, YM: Somewhere between 2007-01-09 and 2007-01-20, 
    ' the WshNetwork object stopped working on CONTROLLER3. 
    ' We could not find any easy way to fix that.
    ' At the same time, it turns out that environment variables 
    ' do work on Windows 2003.
    ' (Apparently, it was some weird configuration problem back in 2005: 
    ' we had only one Windows 2003 computer at that time and it was 
    ' Will's workstation).
    '
    ' In any case, at the time of this writing, 
    ' returning to environment variables 
    ' appears to be the simplest solution to the problem on CONTROLLER3.
    ' Dim wshn As New WshNetwork
    ' CurrentWorkbenchUser = wshn.UserDomain & "\" & wshn.UserName

    CurrentWorkbenchUser = Environ("USERDOMAIN") & "\" & Environ("USERNAME")

End Function
于 2008-10-30T10:29:51.957 に答える
2

環境変数はユーザー セッション内で簡単に変更できるため、有効なままにしておくことはお勧めできません。

于 2008-09-15T22:17:06.850 に答える