私はこの問題に約1週間取り組んでおり、私たちの組織のためにそれを整理しようとしています.
当社の財務部門は IRIS Exchequer を使用しており、コストを計算する必要があります。上記の PHP コードを使用して、次のコード (依存関数を含む) を使用して Excel VBA で動作させることができました。以下に適切に記載されていない場合は、www.sulprobil.com からすべての長い dec to bin 関数を入手しました。次のコード ブロックをコピーしてモジュールに貼り付けると、セルから ExchequerDouble 関数を参照できます。
先に進む前に、上記の C/PHP コードのエラーを 1 つ指摘する必要があります。Significand ループを見ると、次のようになります。
C/PHP: Significand = Significand + 2 ^ (-i)
VBA: Significand = Significand + 2 ^ (1 - i)
テスト中に、答えが非常に近いが、しばしば間違っていることに気付きました。さらにドリルダウンして、記号に絞り込みました。コードをある言語/方法論から別の言語/方法論に翻訳する際の問題であるか、単にタイプミスである可能性がありますが、(1 - i) を追加することですべての違いが生まれました。
Function ExchequerDouble(Val1 As Integer, Val2 As Long) As Double
Dim Int2 As String
Dim Int4 As String
Dim Real48 As String
Dim Exponent As String
Dim Sign As String
Dim Significand As String
'Convert each value to binary
Int2 = LongDec2Bin(Val1, 16, True)
Int4 = LongDec2Bin(Val2, 32, True)
'Concatenate the binary strings to produce a 48 bit "Real"
Real48 = Int4 & Int2
'Calculate the exponent
Exponent = LongBin2Dec(Right(Real48, 8)) - 129
'Calculate the sign
Sign = Left(Real48, 1)
'Begin calculation of Significand
Significand = "1.0"
For i = 2 To 40
If Mid(Real48, i, 1) = "1" Then
Significand = Significand + 2 ^ (1 - i)
End If
Next i
ExchequerDouble = CDbl(((-1) ^ Sign) * Significand * (2 ^ Exponent))
End Function
Function LongDec2Bin(ByVal sDecimal As String, Optional lBits As Long = 32, Optional blZeroize As Boolean = False) As String
'Transforms decimal number into binary number.
'Reverse("moc.LiborPlus.www") V0.3 P3 16-Jan-2011
Dim sDec As String
Dim sFrac As String
Dim sD As String 'Internal temp variable to represent decimal
Dim sB As String
Dim blNeg As Boolean
Dim i As Long
Dim lPosDec As Long
Dim lLenBinInt As Long
lPosDec = InStr(sDecimal, Application.DecimalSeparator)
If lPosDec > 0 Then
If Left(sDecimal, 1) = "-" Then 'negative fractions later..
LongDec2Bin = CVErr(xlErrValue)
Exit Function
End If
sDec = Left(sDecimal, lPosDec - 1)
sFrac = Right(sDecimal, Len(sDecimal) - lPosDec)
lPosDec = Len(sFrac)
Else
sDec = sDecimal
sFrac = ""
End If
sB = ""
If Left(sDec, 1) = "-" Then
blNeg = True
sD = Right(sDec, Len(sDec) - 1)
Else
blNeg = False
sD = sDec
End If
Do While Len(sD) > 0
Select Case Right(sD, 1)
Case "0", "2", "4", "6", "8"
sB = "0" & sB
Case "1", "3", "5", "7", "9"
sB = "1" & sB
Case Else
LongDec2Bin = CVErr(xlErrValue)
Exit Function
End Select
sD = sbDivBy2(sD, True)
If sD = "0" Then
Exit Do
End If
Loop
If blNeg And sB <> "1" & String(lBits - 1, "0") Then
sB = sbBinNeg(sB, lBits)
End If
'Test whether string representation is in range and correct
'If not, the user has to increase lbits
lLenBinInt = Len(sB)
If lLenBinInt > lBits Then
LongDec2Bin = CVErr(x1ErrNum)
Exit Function
Else
If (Len(sB) = lBits) And (Left(sB, 1) <> -blNeg & "") Then
LongDec2Bin = CVErr(xlErrNum)
Exit Function
End If
End If
If blZeroize Then sB = Right(String(lBits, "0") & sB, lBits)
If lPosDec > 0 And lLenBinInt + 1 < lBits Then
sB = sB & Application.DecimalSeparator
i = 1
Do While i + lLenBinInt < lBits
sFrac = sbDecAdd(sFrac, sFrac) 'Double fractional part
If Len(sFrac) > lPosDec Then
sB = sB & "1"
sFrac = Right(sFrac, lPosDec)
If sFrac = String(lPosDec, "0") Then
Exit Do
End If
Else
sB = sB & "0"
End If
i = i + 1
Loop
LongDec2Bin = sB
Else
LongDec2Bin = sB
End If
End Function
Function LongBin2Dec(sBinary As String, Optional lBits As Long = 32) As String
'Transforms binary number into decimal number.
'Reverse("moc.LiborPlus.www") V0.3 PB 16-Jan-2011
Dim sBin As String
Dim sB As String
Dim sFrac As String
Dim sD As String
Dim sR As String
Dim blNeg As Boolean
Dim i As Long
Dim lPosDec As Long
lPosDec = InStr(sBinary, Application.DecimalSeparator)
If lPosDec > 0 Then
If (Left(sBinary, 1) = "1") And Len(sBin) >= lBits Then 'negative fractions later..
LongBin2Dec = CVErr(xlErrVa1ue)
Exit Function
End If
sBin = Left(sBinary, lPosDec - 1)
sFrac = Right(sBinary, Len(sBinary) - lPosDec)
lPosDec = Len(sFrac)
Else
sBin = sBinary
sFrac = ""
End If
Select Case Sgn(Len(sBin) - lBits)
Case 1
LongBin2Dec = CVErr(x1ErrNum)
Exit Function
Case 0
If Left(sBin, 1) = "1" Then
sB = sbBinNeg(sBin, lBits)
blNeg = True
Else
sB = sBin
blNeg = False
End If
Case -1
sB = sBin
blNeg = False
End Select
sD = "1"
sR = "0"
For i = Len(sB) To 1 Step -1
Select Case Mid(sB, i, 1)
Case "1"
sR = sbDecAdd(sR, sD)
Case "0"
'Do Nothing
Case Else
LongBin2Dec = CVErr(xlErrNum)
Exit Function
End Select
sD = sbDecAdd(sD, sD) 'Double sd
Next i
If lPosDec > 0 Then 'now the fraction
sD = "0.5"
For i = 1 To lPosDec
If Mid(sFrac, i, 1) = "1" Then
sR = sbDecAdd(sR, sD)
End If
sD = sbDivBy2(sD, False)
Next i
End If
If blNeg Then
LongBin2Dec = "-" & sR
Else
LongBin2Dec = sR
End If
End Function
Function sbDivBy2(sDecimal As String, blInt As Boolean) As String
'Divide sDecimal by two, blInt = TRUE returns integer only
'Reverse("moc.LiborPlus.www") V0.3 PB 16-Jan-2011
Dim i As Long
Dim lPosDec As Long
Dim sDec As String
Dim sD As String
Dim lCarry As Long
If Not blInt Then
lPosDec = InStr(sDecimal, Application.DecimalSeparator)
If lPosDec > 0 Then
'Without decimal point lPosDec already defines location of decimal point
sDec = Left(sDecimal, lPosDec - 1) & Right(sDecimal, Len(sDecimal) - lPosDec)
Else
sDec = sDecimal
lPosDec = Len(sDec) + 1 'Location of decimal point
End If
If ((1 * Right(sDec, 1)) Mod 2) = 1 Then
sDec = sDec & "0" 'Append zero so that integer algorithm calculates division exactly
End If
Else
sDec = sDecimal
End If
lCarry = 0
For i = 1 To Len(sDec)
sD = sD & Int((lCarry * 10 + Mid(sDec, i, 1)) / 2)
lCarry = (lCarry * 10 + Mid(sDec, i, 1)) Mod 2
Next i
If Not blInt Then
If Right(sD, Len(sD) - lPosDec + 1) <> String(Len(sD) - lPosDec + 1, "0") Then
'frac part Is non - zero
i = Len(sD)
Do While Mid(sD, i, 1) = "0"
i = i - 1 'Skip trailing zeros
Loop
'Insert decimal point again
sD = Left(sD, lPosDec - 1) _
& Application.DecimalSeparator & Mid(sD, lPosDec, i - lPosDec + 1)
End If
End If
i = 1
Do While i < Len(sD)
If Mid(sD, i, 1) = "0" Then
i = i + 1
Else
Exit Do
End If
Loop
If Mid(sD, i, 1) = Application.DecimalSeparator Then
i = i - 1
End If
sbDivBy2 = Right(sD, Len(sD) - i + 1)
End Function
Function sbBinNeg(sBin As String, Optional lBits As Long = 32) As String
'Negate sBin: take the 2's-complement, then add one
'Reverse("moc.LiborPlus.www") V0.3 PB 16-Jan-2011
Dim i As Long
Dim sB As String
If Len(sBin) > lBits Or sBin = "1" & String(lBits - 1, "0") Then
sbBinNeg = CVErr(xlErrValue)
Exit Function
End If
'Calculate 2 's-complement
For i = Len(sBin) To 1 Step -1
Select Case Mid(sBin, i, 1)
Case "1"
sB = "0" & sB
Case "0"
sB = "1" & sB
Case Else
sbBinNeg = CVErr(xlErrValue)
Exit Function
End Select
Next i
sB = String(lBits - Len(sBin), "1") & sB
'Now add 1
i = lBits
Do While i > 0
If Mid(sB, i, 1) = "1" Then
Mid(sB, i, 1) = "0"
i = i - 1
Else
Mid(sB, i, 1) = "1"
i = 0
End If
Loop
'Finally strip leading zeros
i = InStr(sB, "1")
If i = 0 Then
sbBinNeg = "0"
Else
sbBinNeg = Right(sB, Len(sB) - i + 1)
End If
End Function
Function sbDecAdd(sOne As String, sTwo As String) As String
'Sum up two string decimals.
'Reverse("moc.LiborPlus.www") V0.3 PB 16-Jan-2011
Dim lStrLen As Long
Dim s1 As String
Dim s2 As String
Dim sA As String
Dim sB As String
Dim sR As String
Dim d As Long
Dim lCarry As Long
Dim lPosDec1 As Long
Dim lPosDec2 As Long
Dim sF1 As String
Dim sF2 As String
lPosDec1 = InStr(sOne, Application.DecimalSeparator)
If lPosDec1 > 0 Then
s1 = Left(sOne, lPosDec1 - 1)
sF1 = Right(sOne, Len(sOne) - lPosDec1)
lPosDec1 = Len(sF1)
Else
s1 = sOne
sF1 = ""
End If
lPosDec2 = InStr(sTwo, Application.DecimalSeparator)
If lPosDec2 > 0 Then
s2 = Left(sTwo, lPosDec2 - 1)
sF2 = Right(sTwo, Len(sTwo) - lPosDec2)
lPosDec2 = Len(sF2)
Else
s2 = sTwo
sF2 = ""
End If
If lPosDec1 + lPosDec2 > 0 Then
If lPosDecl > lPosDec2 Then
sF2 = sF2 & String(lPosDec1 - lPosDec2, "0")
Else
sF1 = sFl & String(lPosDec2 - lPosDec1, "0")
lPosDec1 = lPosDec2
End If
sF1 = sbDecAdd(sF1, sF2) 'Add fractions as integer numbers
If Len(sF1) > lPosDecl Then
lCarry = 1
sF1 = Right(sF1, lPosDec1)
Else
lCarry = 0
End If
Do While lPosDec1 > 0
If Mid(sF1, lPosDec1, 1) <> "0" Then
Exit Do
End If
lPosDec1 = lPosDec1 - 1
Loop
sF1 = Left(sF1, lPosDec1)
Else
lCarry = 0
End If
lStrLen = Len(sl)
If lStrLen < Len(s2) Then
lStrLen = Len(s2)
sA = String(lStrLen - Len(s1), "0") & s1
sB = s2
Else
sA = s1
sB = String(lStrLen - Len(s2), "0") & s2
End If
Do While lStrLen > 0
d = 0 + Mid(sA, lStrLen, 1) + Mid(sB, lStrLen, 1) + lCarry
If d > 9 Then
sR = (d - 10) & sR
lCarry = 1
Else
sR = d & sR
lCarry = 0
End If
lStrLen = lStrLen - 1
Loop
If lCarry > 0 Then
sR = lCarry & sR
End If
If lPosDec1 > 0 Then
sbDecAdd = sR & Application.DecimalSeparator & sF1
Else
sbDecAdd = sR
End If
End Function
このコードは機能しますが、ときどき (私のテスト データの約 1%)、Excel アドインの Iris の EntDouble 関数と比較して数ペニーの費用がかかります。誰かがそれを理解できない限り、私はこれを精度に帰します。
最終的にこれを VBA で動作させることは、すべてが機能していることを確認するための私の概念実証でした。この機能の対象プラットフォームは SQL Server でした。Exchequer DB が SQL Server にリンクされている場合は、この関数を Pervasive DB のデータに対して直接実行できるはずです。私の場合、過去 2.5 年分のトランザクション データを SQL Server の静的テーブルにダンプしますが、このデータを使用するのは年に 1 回だけなので、問題にはなりません。次の 2 つの関数で解決できます。精度の点では、それらは上記の VBA コードと同等であり、いくつかは数ペニーの差がある場合もありますが、99% の確率でまったく同じようです。
CREATE FUNCTION dbo.FUNCTION_Exchequer_Double
(
@Val1 AS SmallInt,
@Val2 AS BigInt
)
RETURNS Decimal(38, 10)
AS
BEGIN
-- Declare and set decoy variables
DECLARE @Val1_Decoy AS SmallInt
DECLARE @Val2_Decoy AS BigInt
SELECT @Val1_Decoy = @Val1,
@Val2_Decoy = @Val2
-- Declare other variables
DECLARE @Val1_Binary AS Varchar(16)
DECLARE @Val2_Binary AS Varchar(32)
DECLARE @Real48_Binary AS Varchar(48)
DECLARE @Real48_Decimal AS BigInt
DECLARE @Exponent AS Int
DECLARE @Sign AS Bit
DECLARE @Significand AS Decimal(19, 10)
DECLARE @BitCounter AS Int
DECLARE @Two As Decimal(38, 10) -- Saves us casting inline in the code
DECLARE @Output AS Decimal(38, 10)
-- Convert values into two binary strings of the correct length (Val1 = 16 bits, Val2 = 32 bits)
SELECT @Val1_Binary = Replicate(0, 16 - Len(dbo.FUNCTION_Convert_To_Base(Cast(@Val1_Decoy AS Binary(2)), 2)))
+ dbo.FUNCTION_Convert_To_Base(Cast(@Val1_Decoy AS Binary(2)), 2),
@Val2_Binary = Replicate(0, 32 - Len(dbo.FUNCTION_Convert_To_Base(Cast(@Val2_Decoy AS Binary(4)), 2)))
+ dbo.FUNCTION_Convert_To_Base(Cast(@Val2_Decoy AS Binary(4)), 2)
-- Find the decimal value of the new 48 bit number and its binary value
SELECT @Real48_Decimal = @Val2_Decoy * Power(2, 16) + @Val1_Decoy
SELECT @Real48_Binary = @Val2_Binary + @Val1_Binary
-- Determine the Exponent (takes the first 8 bits and subtracts 129)
SELECT @Exponent = Cast(@Real48_Decimal AS Binary(1)) - 129
-- Determine the Sign
SELECT @Sign = Left(@Real48_Binary, 1)
-- A bit of setup for determining the Significand
SELECT @Significand = 1,
@Two = 2,
@BitCounter = 2
-- Determine the Significand
WHILE @BitCounter <= 40
BEGIN
IF Substring(@Real48_Binary, @BitCounter, 1) Like '1'
BEGIN
SELECT @Significand = @Significand + Power(@Two, 1 - @BitCounter)
END
SELECT @BitCounter = @BitCounter + 1
END
SELECT @Output = Power(-1, @Sign) * @Significand * Power(@Two, @Exponent)
-- Return the output
RETURN @Output
END
CREATE FUNCTION dbo.FUNCTION_Convert_To_Base
(
@value AS BigInt,
@base AS Int
)
RETURNS Varchar(8000)
AS
BEGIN
-- Code from http://dpatrickcaldwell.blogspot.co.uk/2009/05/converting-decimal-to-hexadecimal-with.html
-- some variables
DECLARE @characters Char(36)
DECLARE @result Varchar(8000)
-- the encoding string and the default result
SELECT @characters = '0123456789abcdefghijklmnopqrstuvwxyz',
@result = ''
-- make sure it's something we can encode. you can't have
-- base 1, but if we extended the length of our @character
-- string, we could have greater than base 36
IF @value < 0 Or @base < 2 Or @base > 36
RETURN Null
-- until the value is completely converted, get the modulus
-- of the value and prepend it to the result string. then
-- devide the value by the base and truncate the remainder
WHILE @value > 0
SELECT @result = Substring(@characters, @value % @base + 1, 1) + @result,
@value = @value / @base
-- return our results
RETURN @result
END
私の VBA または SQL コードを自由に使用してください。上記の PHP に変換した人は、本当に大変な作業を行いました。誰かが何かを改善する方法を見つけた場合は、私に知らせてください。このコードを可能な限り完璧にすることができます。
ありがとう！