私はすでにこれを提出したので、あなたは私がカンニングを手伝うことはありません. これが正しいかどうか疑問に思っています:
課題: 従業員の名前と給与のリストを入力し、平均 (平均) 給与と、平均を上回る給与と下回る給与の数を決定します。
計画: 名前と給与の入力を許可する 平均を計算する 値を並べ替える 平均より上の値をカウントする 平均より下の値をカウントする
//This program will allow a user to input an employee name and salary
//The output will contain the mean salary
//as well as the number of salaries above and below the mean
//
//Arrays Used:
//Name(K) = Array for employee names
//Salary(K) = Array for salaries
//
//Variables Used:
//Mean = Mean of all employees Salaries
//UpMean = Number of Employees making more than the mean
//DwnMean = Number of Employees making less than the mean
//Sum = Sum of all salaries
//CountM = Counter for Mean
//CountUp = Counter for # of salaries above mean
//CountDwn = Counter for # of salaries below mean
Main
Call WelcomeMessage
Call InputData
Call Calculate
Call OutputData
End Program
WelcomeMessage
Write, “Beginning the Salary Program”
End WelcomeMessage
InputData
Declare Name(100) Of Strings
Declare Salary(100) Of Real
Declare Mean, UpMean, DwnMean As Real
Set Sum = 0
Set CountM = 0
Set CountUp = 0
Set CountDwn = 0
Write, "Enter Employee name and Salary."
Write, "Enter *,0 when done."
Input Name(K), Salary(K)
While Name(K) <> "*"
Set CountM = CountM + 1
Set Sum = Sum + Salary
Write, "Enter Employee name and Salary."
Write, "Enter *,0 when done."
Input Name(K), Salary(K)
End While
End InputData
Calculation
//Here Mean is found
Set Mean = Sum / CountM
//Here Number of Employees making more than the mean is found
For K = Step 1 to CountM
If Salary(K) > Mean Then
Set CountUp = CountUp + 1
End If
//Here Number of Employees making more than the mean is found
Set CountDwn = CountM - CountUp
//The above algorythm doesn't account for the possibility
//of someone making exactly the average so subtract 1 to reconcile
If Salary(K) = Mean Then
Set CountDwn = CountDwn - 1
End If
End Calculation
OutputData
Write, "There were," CountM, "salaries entered."
Write, "The mean salary is:", Mean
Write, "There are", CountUp, "employees who make more than the average"
Write, "There are", CountDwn, "employees who make less than the average"
End OutputData