私はPythonにプライベート変数を許可させようとしているので、クラスの開始時に配置するこのデコレータを作成して、すべての関数が追加のプライベートパラメータを取得し、必要に応じて変更できるようにしました。私の知る限り、クラスの外部から変数を取得することは不可能ですが、私はプロではありません。
誰かがプライベートオブジェクトにハッキングしてそこから値を取得する方法を見つけることができますか？これよりも良い方法はありますか？
Python 2.7
#this is a decorator that decorates another decorator. it makes the decorator
#not loose things like names and documentation when it creates a new function
def niceDecorator(decorator):
def new_decorator(f):
g = decorator(f)
g.__name__ = f.__name__
g.__doc__ = f.__doc__
g.__dict__.update(f.__dict__)
return g
new_decorator.__name__ = decorator.__name__
new_decorator.__doc__ = decorator.__doc__
new_decorator.__dict__.update(decorator.__dict__)
return new_decorator
@niceDecorator
#this is my private decorator
def usePrivate(cls):
prv=type('blank', (object,), {})
#creates a blank object in the local scope
#this object will be passed into every function in
#the class along with self which has been renamed
#as pbl (public).
@niceDecorator
#this is the decorator that gets applied to every function
#in the class. in makes it also accept the private argument
def decorate(func):
def run(pub, *args, **kwargs):
return func(pub,prv, *args, **kwargs)
return run
#this loops through every function in the class and applies the decorator
for func in cls.__dict__.values():
if callable(func):
setattr(cls, func.__name__, decorate(getattr(cls, func.__name__)))
return cls
#this is the class we are testing the private decorator with.
#this is what the user would program
@usePrivate
class test():
#sets the value of the private variable
def setValue(pbl,prv,arg):
#pbl (public) is another name for self
#prv (private) acts just like self except its private
prv.test=arg
#gets the value of the private variable
def getValue(pbl,prv):
return prv.test
a=test()
a.setValue(3)
print a.getValue()