3

私のデータベースは次のようになります。

[foods]
foods_id, foods_name, groups_id, producers_id

[producers]
producers_id, producers_name

[groups]
groups_id, groups_name

PHP:

<?php
$producers = mysql_query('SELECT p.producers_name,p.producers_id FROM foods as f,producers as p WHERE p.producers_id = f.producers_id AND f.groups_id = 1 GROUP BY p.producers_name');
    //list the producer...
    while($row = mysql_fetch_array($producers, MYSQL_ASSOC)){
        $foods = mysql_query('SELECT foods_id, foods_name FROM foods WHERE producers_id = '.$row['producers_id'].' ORDER BY foods_name ASC');       
        while($row2 = mysql_fetch_array($foods, MYSQL_ASSOC)){
            //list the foods under this producer...
        }
    }
?>

ゴール：

PRODUCER A
   FOOD A
   FOOD B
   FOOD C
PRODUCER B
   FOOD D
   FOOD E
PRODUCER C
   FOOD F
...

解決： 

<?php
$res = mysql_query('SELECT f.foods_id, f.foods_name, p.producers_id, p.producers_name FROM foods f, producers p WHERE p.producers_id = f.producers_id AND f.groups_id = '.$_GET['g'].' ORDER BY p.producers_name ASC, f.foods_name ASC');       
$xproducers = array();
while($row = mysql_fetch_array($res , MYSQL_ASSOC)){
    if(!array_key_exists($row['producers_id'],$xproducers)){
        $xproducers[$row['producers_id']] = array('id'=>$row['producers_id'],'name'=>$row['producers_name'],'foods'=>array());
    }
    array_push($xproducers[$row['producers_id']]['foods'],array('id'=>$row['foods_id'],'name'=>$row['foods_name']));
}
?>

このソリューションは私にとって十分に高速です。おそらく完璧ではないかもしれませんが、うまく機能します:)素晴らしい助けをありがとうございました!

乾杯

4

2 に答える 2

1

最初に選択する理由がわかりません。これは同じデータを取得します。

$res = mysql_query('SELECT f.foods_id, f.foods_name, p.producers_id, p.producers_name FROM foods f, producers p WHERE p.producers_id = f.producers_id AND f.groups_id = 1');       
    while($row = mysql_fetch_array($res , MYSQL_ASSOC)){
        $producers[$row['producers_id']][$row['foods_id']] = $row;
    }
于 2012-05-24T19:29:46.527 に答える
0

私はただするだろう

mysql_query('SELECT producers_name, producers_id
FROM producers
WHERE producers_id IN
(SELECT producers_id FROM foods WHERE groups_id = 1)');

それははるかに速く動作するはずです。

頑張ってください！

于 2012-05-24T19:20:19.737 に答える