1

Group By以下のように、とに苦労してNullいます。

私は以下のような2つのテーブルを持っています 

Table : 1 accountmast       
companyID   accname             category    
102         PURCHASE ACCOUNT    Purchase Account    
102         LOCAL PURCHASE      Purchase Account    
102         SALES ACCOUNT       Sales Account   

Table: 2 ledger     
companyID   name                debit   credit
102         PURCHASE ACCOUNT    4742.3  
102         LOCAL PURCHASE      51106   
102         SALES ACCOUNT               8010
102         SALES ACCOUNT               4330000
102         PURCHASE ACCOUNT    5480000

そして、私は以下のように質問しました：

select  
case    
when a.catagory ='Purchase Account' then    
l.name  
end as PurchaseAccount, 

case    
when a.catagory ='Purchase Account' then    
sum(coalesce(l.debit,0))-sum(coalesce(l.credit,0) ) 
end as PurAmt,  

case    
when a.catagory = 'Sales Account' then  
l.name      
end as SalesAccount,    
case    
when a.catagory = 'Sales Account' then  
sum(coalesce(l.credit,0))-sum(coalesce(l.debit,0) ) 
end as SalesAmt 

from ledger l join accountmast a    
on l.companyID=a.companyID  
and l.name = a.accname  
where l.companyID=102   
and a.catagory IN('Purchase Account','Sales Account')   
group by l.name,a.catagory

そして結果は次のとおりです。

Purchase Account    PurAmt          Sales Account   SalesAmt
LOCAL PURCHASE      51106.00         NULL           NULL
PURCHASE ACCOUNT    5484742.30       NULL           NULL
NULL                NULL            SALES ACCOUNT  4338010.00

そして、要件は次のとおりです。

Purchase Account    PurAmt           Sales Account   SalesAmt
LOCAL PURCHASE      51106.00         SALES ACCOUNT   4338010.00
PURCHASE ACCOUNT    5484742.30

解決策は何ですか？

私が使用する場合Group By、それはNull値がテーブルの列を関連付けることを可能にします。

を使用するMAXとMIN、単一のレコードが表示されます。私は何をしなければなりませんか？

誰かがより良い解決策を持っているなら、提案してください。

4

2 に答える 2

2 
WITH    q AS
        (
        SELECT  am.category, l.name,
                CASE am.category WHEN 'Purchase Account' THEN amt ELSE -amt END
        FROM    accountmast am
        CROSS APPLY
                (
                SELECT  name, SUM(COALESCE(credit, 0) - COALESCE(debit, 0)) AS amt
                FROM    ledger l
                WHERE   l.name = am.accname
                        AND l.companyId = am.companyId
                GROUP BY
                        name
                ) l
        WHERE   am.companyId = 102
        )
SELECT  l1.name, l1.amt, l2.name, l2.amt
FROM    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   category = 'Purchase account'
        ) l1
FULL JOIN
        (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   category = 'Sales account'
        ) l2
ON      l2.rn = l1.rn
于 2012-06-06T07:42:50.597 に答える
0

注: これは回答ではありません。Quassnoi の検討の参考になります。

ここで、あなたの考慮のために私が行った特定の修正。

WITH    q AS
(
SELECT  am.catagory, l.name,
CASE am.catagory WHEN 'Purchase Account' THEN Amount ELSE -Amount     END as Amount -- Here I provide the column name and alter the Column
FROM    accountmast am
    CROSS APPLY
    (
    SELECT  name, SUM(COALESCE(debit, 0) - COALESCE(credit, 0)) AS Amount --Reverse the sum function which is oppose of yours. And your's shows the value in minus.
    FROM    ledger l
    WHERE   l.name = am.accname
    AND l.companyId = am.companyId
    GROUP BY
             name
    ) l
    WHERE   am.companyId = 102
)
SELECT  l1.name as PurACC, l1.Amount as PurAmt, l2.name as SalACC, l2.Amount as SalAmt -- alter the columns for Binding Purpose.
FROM
    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   catagory = 'Purchase account'
    ) l1
FULL JOIN
    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   catagory = 'Sales account'
    ) l2
ON l2.rn = l1.rn

上記の変更は重要です。それ以外の場合、回答は間違ったままになり、エラー チェックがスローされます。

于 2012-06-06T13:21:42.713 に答える