Spring Data と Hibernate を使用していますが、セット ID でエンティティを保存しようとするとエラーが発生します。
org.springframework.dao.InvalidDataAccessApiUsageException: detached entity passed to persist: com.snp.cm.persistency.contact.Contact; nested exception is org.hibernate.PersistentObjectException: detached entity passed to persist: com.snp.cm.persistency.contact.Contact
at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:668)
JpaRepositories を介してエンティティを更新する方法を教えてください。または、どの設定を見逃していますか?
persistence.xml:
<?xml version="1.0" encoding="UTF-8"?> <persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0" xmlns="http://java.sun.com/xml/ns/persistence">
<persistence-unit name="contactManagerPU">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.snp.cm.persistency.contact.Contact</class>
<class>com.snp.cm.persistency.contact.TelephoneNumber</class>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="hibernate.max_fetch_depth" value="3" />
</properties>
</persistence-unit>
春のコンテキスト:
<?xml version="1.0" encoding="UTF-8" standalone="no"?><beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:p="http://www.springframework.org/schema/p" xmlns:jdbc="http://www.springframework.org/schema/jdbc"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.0.xsd"
default-lazy-init="true">
<import resource="classpath*:META-INF/spring/dbs-repository-context.xml" />
<!-- Activates JPA's @PersistenceContext and @PersistenceUnit (if available)
annotations to be detected in bean classes. -->
<context:annotation-config />
<!-- Enable Transaction using @Transactional annotation -->
<tx:annotation-driven />
<bean id="daTM"
class="org.springframework.jdbc.datasource.DataSourceTransactionManager"
p:dataSource-ref="dataSource" />
<!-- Create local transaction manager -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
p:entityManagerFactory-ref="entityManagerFactory" lazy-init="true"
p:dataSource-ref="dataSource" />
<!-- Create EntityManagerFactory for injection into services. -->
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:dataSource-ref="dataSource" p:persistenceXmlLocation-ref="persistenceXmlLocation">
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
</bean>
</property>
</bean>
<!-- Database access configuration -->
<bean id="persistenceXmlLocation" class="java.lang.String">
<constructor-arg value="classpath*:META-INF/persistence.xml"></constructor-arg>
</bean>
<context:property-placeholder
location="classpath:META-INF/spring/jdbc.properties" />
<!-- Dev's env DataSource -->
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close">
<property name="driverClassName" value="${jdbc.driver}" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
</bean>
別のプロジェクトで OpenJpa を使用しましたが、そのような問題はありませんでした。エンティティに ID が設定されている場合、「保存」メソッドは作成および更新を行いました。では、どうすればオブジェクトを更新できますか? 独自の更新方法を実装する必要がありますか?
失敗したテスト:
@Test
public void testRepositorySaveMethod() {
Contact contact = new Contact();
contact.setLastName("Carter");
contact.setName("John");
contact.setNickName(null);
contact = this.contactRepository.save(contact);
Assert.assertNotNull(contact.getContactId());
TelephoneNumber telephoneNumber1 = new TelephoneNumber();
telephoneNumber1.setTelephoneNumber("777 7777777");
telephoneNumber1.setContact(contact);
telephoneNumber1.setTelephoneType(TelephoneType.HOME);
this.telephoneNumberRepository.save(telephoneNumber1); // failes cause contact has already id
contact = this.contactRepository.findOne(contact.getContactId());
Assert.assertEquals(1, contact.getTelephoneNumbers().size());
}