私が取り組んでいる c# アプリでは、ObservableDictionary を使用しています。これでのパフォーマンスは、その機能に対応するのに十分な速さではありません。ObservableDictionary は非常に迅速にやり取りされ (要素の削除、追加、および更新)、変更が行われるたびにソートする必要があります。ObservableDictionary に使用できる代替手段はありますか?パフォーマンスに重点を置きながら、迅速に並べ替えることができますか?
質問する
577 次
1 に答える
6
追加/更新または削除が行われるたびに再バインドが発生しない独自のものを作成するのは非常に簡単です。まさにこの理由のために、私たちは自分自身を書きました。基本的に、コレクション内のすべてのオブジェクトが処理されるまで、変更が行われたという通知を無効にしてから、通知を生成します。こんな感じです。ご覧のとおり、MVVM フレームワーク ライブラリとして MvvmLight を使用します。これにより、パフォーマンスが大幅に向上します。
using System;
using System.Collections.Generic;
using System.Collections.ObjectModel;
using System.Collections.Specialized;
using System.Linq;
using FS.Mes.Client.Mvvm.MvvmTools.MvvmLight;
namespace FS.Mes.Client.Mvvm.MvvmTools
{
/// <summary>
/// Our implementation of ObservableCollection. This fixes one significant limitation in the .NET Framework implementation. When items
/// are added or removed from an observable collection, the OnCollectionChanged event is fired for each item. Depending on how the collection
/// is bound, this can cause significant performance issues. This implementation gets around this by suppressing the notification until all
/// items are added or removed. This implementation is also thread safe. Operations against this collection are always done on the thread that
/// owns the collection.
/// </summary>
/// <typeparam name="T">Collection type</typeparam>
public class FsObservableCollection<T> : ObservableCollection<T>
{
#region [Constructor]
/// <summary>
/// Constructor
/// </summary>
public FsObservableCollection()
{
DispatcherHelper.Initialize();
}
#endregion
#region [Public Properties]
/// <summary>
/// Gets or sets a property that determines if we are delaying notifications on updates.
/// </summary>
public bool DelayOnCollectionChangedNotification { get; set; }
#endregion
/// <summary>
/// Add a range of IEnumerable items to the observable collection and optionally delay notification until the operation is complete.
/// </summary>
/// <param name="items"></param>
/// <param name="delayCollectionChangedNotification">Value indicating whether delay notification will be turned on/off</param>
public void AddRange(IEnumerable<T> items, bool delayCollectionChangedNotification = true)
{
if (items == null)
throw new ArgumentNullException("items");
DoDispatchedAction(() =>
{
DelayOnCollectionChangedNotification = delayCollectionChangedNotification;
// Do we have any items to add?
if (items.Any())
{
try
{
foreach (var item in items)
this.Add(item);
}
finally
{
// We're done. Turn delay notification off and call the OnCollectionChanged() method and tell it we had a 'dramatic' change
// in the collection.
DelayOnCollectionChangedNotification = false;
this.OnCollectionChanged(new NotifyCollectionChangedEventArgs(NotifyCollectionChangedAction.Reset));
}
}
});
}
/// <summary>
/// Clear the items in the ObservableCollection and optionally delay notification until the operation is complete.
/// </summary>
public void ClearItems(bool delayCollectionChangedNotification = true)
{
// Do we have anything to remove?
if (!this.Any())
return;
DoDispatchedAction(() =>
{
try
{
DelayOnCollectionChangedNotification = delayCollectionChangedNotification;
this.Clear();
}
finally
{
// We're done. Turn delay notification off and call the OnCollectionChanged() method and tell it we had a 'dramatic' change
// in the collection.
DelayOnCollectionChangedNotification = false;
this.OnCollectionChanged(new NotifyCollectionChangedEventArgs(NotifyCollectionChangedAction.Reset));
}
});
}
/// <summary>
/// Override the virtual OnCollectionChanged() method on the ObservableCollection class.
/// </summary>
/// <param name="e">Event arguments</param>
protected override void OnCollectionChanged(NotifyCollectionChangedEventArgs e)
{
DoDispatchedAction(() =>
{
if (!DelayOnCollectionChangedNotification)
base.OnCollectionChanged(e);
});
}
/// <summary>
/// Makes sure 'action' is executed on the thread that owns the object. Otherwise, things will go boom.
/// </summary>
///<param name="action">The action which should be executed</param>
private static void DoDispatchedAction(Action action)
{
DispatcherHelper.CheckInvokeOnUI(action);
}
}
}
于 2012-09-10T18:27:09.947 に答える