私はこれを試しました:
$cid = mysql_insert_id($this->result);
$this->result = "<div class='alert alert-success'>" . sprintf(_('Successfully added user id <b>%s</b> to the database.'), $cid) . "</div>";
しかし、私はこのエラーしか受け取りません:
警告: mysql_insert_id(): 指定された引数は有効な MySQL-Link リソースではありません
これは関数全体です (挿入されたデータの ID を取得するために、この$cid = mysql_insert_id($this->result);を追加しました):
private function adduser() {
if (!empty($this->error)) return false;
$params = array(
':user_level' => parent::getOption('default-level'),
':name' => $this->name,
':email' => $this->email,
':username' => $this->username,
':password' => parent::hashPassword($this->password)
);
parent::query("INSERT INTO `login_users` (`user_level`, `name`, `email`, `username`, `password`)
VALUES (:user_level, :name, :email, :username, :password);", $params);
$shortcodes = array(
'site_address' => SITE_PATH,
'full_name' => $this->name,
'username' => $this->username,
'email' => $this->email,
'password' => $this->password
);
$subj = parent::getOption('email-add-user-subj');
$msg = parent::getOption('email-add-user-msg');
if(!parent::sendEmail($this->email, $subj, $msg, $shortcodes))
$this->error = _('ERROR. Mail not sent');
$cid = mysql_insert_id($this->result);
$this->result = "<div class='alert alert-success'>" . sprintf(_('Successfully added user <b>%s</b> to the database. Credentials sent to user.'), $cid) . "</div>";
}
これはデータベースへの接続です。
<?php
$host = "xxx";
$dbName = "xxx";
$dbUser = "xxx";
$dbPass = "xxx";
?>