I am trying to create a side menu using jQuery in which the div sideBarMinified
will be hidden and hover and will display the sideBar
. On mouseout, sideBar
will be hidden and sideBarMinified
will be displayed.
Here's what I have :
HTML :
<div class="sideBarMinified">
<div class="topClear"> </div>
<img src="images/miniLogo.png">
</div>
<div class="sideBar">
<div class="topClearBig"> </div>
<img src="images/logo.png">
<div class="menuClear"></div>
<a href="#">Sample</a>
</div>
JS :
$(document).ready(function() {
$(".sideBar").hide();
$.backstretch(["images/cover.jpg"],{fade:2000});
$(".sideBarMinified").mouseover(function(){
$(".sideBar").show();
$(".sideBarMinified").animate({left: "-=60px"}, 0 );
$(".sideBar").animate({left: "+=272px"}, 500 );
});
$(".sideBar").mouseout(function() {
$(".sideBar").animate({left: "-=272px"}, 500 );
$(".sideBarMinified").animate({left: "+=60px"}, 700 );
});
});
CSS :
div.sideBarMinified {
position:absolute;
left:0px;
width:20px;
height:100%;
background-color:rgba(208,198,168,0.9);
border-right:1px solid #333333;
padding:0 15px 0 15px;
z-index:999;
}
div.sideBar {
position:absolute;
left:-272px;
width:272px;
height:100%;
background-color:rgba(208,198,168,0.9);
padding:0 2px 0 45px;
z-index:500;
}
The issue is when I hover on the <a>
tag, the div sideBar
is hidden and the div sideBarMinified
is moving to the left. What is wrong with my code?