android - selectQuery に従うことに問題はありますか?

Question

int getIdForSong(Song song){

    String selectQuery = "SELECT id FROM " + TABLE_SONG + " WHERE " + SONG_TITLE + "=" + song.getSongTitle() + " AND " + ARTIST_NAME + "=" + song.getArtistName();
    SQLiteDatabase db = this.getReadableDatabase();
    Cursor cursor = db.rawQuery(selectQuery, null);
    int id = Integer.parseInt(cursor.getString(0));
    return id;
}

「=」の近くで例外が発生しています。誰？

Answer 1

selectQuery の値を次のように変更します。

"SELECT id FROM " + TABLE_SONG + " WHERE " + SONG_TITLE + " = '" + song.getSongTitle() + "' AND  '" + ARTIST_NAME + "' = '" + song.getArtistName() + "'";

Answer 2

CursorOutOfBoundExceptionの場合、

カーソル後cursor=db.rawQuery（selectQuery、null）; 、

if（null！= cursor && cursor.moveToFirst（））{

  int id = Integer.parseInt(cursor.getString(0));
  return id;

}

Answer 3

これを試して

int getIdForSong(Song song){

String selectQuery = "SELECT id FROM " + TABLE_SONG + " WHERE " + SONG_TITLE + "= ' " + song.getSongTitle() + "' AND " + ARTIST_NAME + "= ' " + song.getArtistName()+" ' ";
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);
int id = Integer.parseInt(cursor.getString(0));
return id;
}