0

私の目的は、HomeNumberとOfficeNumberの両方を含む1つのレコードを作成することであり、PersonIDを保持して顧客テーブルを参照します。UNIONを使用するのではなく、2つのネストされたサブクエリからのselectクエリを使用する必要があると思います。

返される結果は次のようになります。

1A370535-9432-45B9-8F08-004F040EE196    ''          ''
1A370535-9432-45B9-8F08-004F040EE196    6127319561  ''
E8FA1667-416C-4639-ADDC-02143D651B4E    ''          6512096719
E8FA1667-416C-4639-ADDC-02143D651B4E    6515786963  ''

ここに私の質問：

    SELECT PhoneNumbers.PersonID, PhoneNumbers.HomeNum, PhoneNumbers.OfficeNum
    FROM (
      SELECT PhoneHub.PersonID, ISNULL(PhoneHub.PhoneNbr, '') AS HomeNum, '' AS OfficeNum
      FROM 
        --PhoneType INNER JOIN 
        PhoneHub --ON PhoneType.ID = PhoneHub.TypeID 
      WHERE 
        (PhoneHub.FranID = @FranID) AND
        (PhoneHub.TypeID = '28321161-668e-4a56-90be-67a146fa1353') -- Home# ID
      UNION
      SELECT PhoneHub.PersonID, '' AS HomeNum, ISNULL(PhoneHub.PhoneNbr, '') AS OffNum
      FROM 
        --PhoneType AS PhoneType_2 INNER JOIN 
        PhoneHub --AS PhoneHub ON PhoneType_2.ID = PhoneHub.TypeID
      WHERE 
        (PhoneHub.FranID = @FranID) AND
        (PhoneHub.TypeID = '02a4125b-b968-4dc6-9734-7f75f45f7635') --Office# ID
     ) AS PhoneNumbers  
     ORDER BY PhoneNumbers.PersonID

テーブルスキーマ-PhoneHub

PK  ID          uniqueidentifier    
FK  FranID      uniqueidentifier      Franchise.ID
FK  PersonID    uniqueidentifier      Customer.ID   
FK  TypeID      uniqueidentifier      PhoneType.ID
PhoneNbr    nvarchar(20)    
PhoneExt    nvarchar(10)    
IsDefault   bit
4

2 に答える 2

1

これはピボット要件のように見えます。

   SELECT PersonID,
          Max(case when TypeID = '28321161-668e-4a56-90be-67a146fa1353'
                   then PhoneNbr End) HomeNum,
          Max(case when TypeID = '02a4125b-b968-4dc6-9734-7f75f45f7635'
                   then PhoneNbr End) OfficeNum
    FROM
      PhoneHub
    WHERE 
      PhoneHub.FranID = @FranID
    GROUP BY PersonID
于 2012-11-02T18:12:37.657 に答える
0 
Select  a.PersonID,Coalesce(home.PhoneNbr, '') AS HomeNum,Coalesce(office.PhoneNbr, '') AS OffNum from
(
      SELECT PhoneHub.PersonID
      FROM 
        PhoneHub
      WHERE 
        (PhoneHub.FranID = @FranID) AND
        (PhoneHub.TypeID = '28321161-668e-4a56-90be-67a146fa1353')
      UNION
      SELECT PhoneHub.PersonID
      FROM 
        PhoneHub
      WHERE 
        (PhoneHub.FranID = @FranID) AND
        (PhoneHub.TypeID = '02a4125b-b968-4dc6-9734-7f75f45f7635')
) as a
left join    PhoneHub home on   (home.PersonID = a.PersonID)  and  (home.FranID = @FranID) AND (home.TypeID = '28321161-668e-4a56-90be-67a146fa1353')
left join    PhoneHub office on (office.PersonID = a.PersonID)  and (office.FranID = @FranID) AND (office.TypeID = '02a4125b-b968-4dc6-9734-7f75f45f7635')
order by a.PersonID
于 2012-11-02T18:23:20.083 に答える