http://mascwt.oicp.net:7080/Monitoring/Data/getOrgData/ URLアドレスです。URL の戻りデータにアクセスするには? URL は json データを返す必要があります。戻りデータにアクセスできます。私はアンドロイドHttpClientを使いたいです。どうしてですか?
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1182 次
2 に答える
1
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
new AsyncTask<Void,Void,Void>() {
@Override
protected Void doInBackground(Void... params) {
// TODO Auto-generated method stub
JSONObject jObject = getJSONfromURL("http://mascwt.oicp.net:7080/Monitoring/Data/getOrgData/");
return null;
}
}.execute();
}
public JSONObject getJSONfromURL(String url) {
// initialize
InputStream is = null;
String result = "";
JSONObject jArray = null;
// http post
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection " + e.toString());
}
// convert response to string
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result = sb.toString();
} catch (Exception e) {
Log.e("log_tag", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jArray = new JSONObject(result);
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data " + e.toString());
}
return jArray;
}
于 2012-11-12T10:03:03.960 に答える
1
public class WebServices {
public JSONObject RequestUrl(String url) {
JSONObject jsonResponse = null;
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
Log.v("URL request", "--->" + url);
URI uri = new URI(url);
HttpGet httpget = new HttpGet(uri);
httpget.setHeader("Accept", "application/json");
httpget.setHeader("Content-type", "application/json; charset=utf-8");
HttpResponse response = httpClient.execute(httpget);
HttpEntity responseEntity = response.getEntity();
String changeTIDRec = EntityUtils.toString(responseEntity);
System.out.println(changeTIDRec);
jsonResponse = new JSONObject(changeTIDRec);
Log.v("WebService", "Response : " + jsonResponse);
} catch (Exception e) {
e.printStackTrace();
}
return jsonResponse;
}}
于 2012-11-12T10:06:09.827 に答える