私はこのような基本的な IRC ボットを持っています (以下を参照) _5_mins
。LoopingCall
import sys
import re
from twisted.internet import reactor, task, defer, protocol
from twisted.python import log
from twisted.words.protocols import irc
from twisted.application import internet, service
import time
HOST, PORT = 'irc.freenode.net', 6667
class IrcProtocol(irc.IRCClient):
nickname = 'BOTSNAME'
password = 'NICKPASSWORD'
timeout = 600.0
def signedOn(self):
pMess = "IDENTIFY %s" % self.password
self.msg("NickServ",pMess)
time.sleep(10)
for channel in self.factory.channels:
self.join(channel)
def _5_mins(self):
self.msg(self.factory.channels[0],"5 minutes have elapsed")
class IrcFactory(protocol.ReconnectingClientFactory):
channels = ['#BOTCHANNEL']
protocol = IrcProtocol
if __name__ == '__main__':
reactor.connectTCP(HOST, PORT, IrcFactory())
log.startLogging(sys.stdout)
reactor.run()
elif __name__ == '__builtin__':
application = service.Application('IrcBot')
ircService = internet.TCPClient(HOST, PORT, IrcFactory())
ircService.setServiceParent(application)
signedOn
関数で関数の動作を変更するにはどうすればtask.LoopingCall
よいですか、またはより良い方法がありますか?
編集:私は解決策に本当に近かったです。以下は私が行ったことです
def signedOn(self):
pMess = "IDENTIFY %s" % self.password
self.msg("NickServ",pMess)
time.sleep(10)
for channel in self.factory.channels:
self.join(channel)
lc = task.LoopingCall(self._5_mins)
lc.start(self.timeout)