以下は、異なる順序でロックを取得しようとする 2 つのロックと 2 つのスレッドを使用した不自然な例です。タイムアウトがないと、コードはデッドロックします。
public static void main(String[] args) throws Exception {
final ReentrantLock lock1 = new ReentrantLock();
final ReentrantLock lock2 = new ReentrantLock();
Runnable try1_2 = getRunnable(lock1, "lock 1", lock2, "lock 2");
Runnable try2_1 = getRunnable(lock2, "lock 2", lock1, "lock 1");
new Thread(try1_2).start();
new Thread(try2_1).start();
}
private static Runnable getRunnable(final ReentrantLock lock1, final String lock1Name, final ReentrantLock lock2, final String lock2Name) {
return new Runnable() {
@Override
public void run() {
try {
if (lock1.tryLock(1, TimeUnit.SECONDS)) {
System.out.println(lock1Name + " acquired in thread " + Thread.currentThread());
if (lock2.tryLock(1, TimeUnit.SECONDS)) {
System.out.println(lock2Name + " acquired in thread " + Thread.currentThread());
Thread.sleep(2000);
} else {
System.out.println("Could not acquire "+lock2Name + " in thread " + Thread.currentThread());
lock1.unlock();
System.out.println(lock1Name + " released in thread " + Thread.currentThread());
}
} else {
System.out.println("Could not acquire " + lock1Name + " in thread " + Thread.currentThread());
}
} catch (InterruptedException e) {
//you should not ignore it
} finally {
if (lock1.isHeldByCurrentThread()) lock1.unlock();
if (lock2.isHeldByCurrentThread()) lock2.unlock();
}
}
};
}