次のコードを使用して、Web サイトにログインし、JSON を使用して応答を取得しようとしています。
@try {
if([[txtUsername text] isEqualToString:@""] || [[txtPassword text] isEqualToString:@""] ) {
[self alertStatus:@"Please enter both Username and Password" :@"Login Failed!"];
} else {
NSString *post =[[NSString alloc] initWithFormat:@"username=%@&password=%@",[txtUsername text],[txtPassword text]];
NSLog(@"PostData: %@",post);
NSURL *url=[NSURL URLWithString:@"https://yedion.afeka.ac.il/yedion/fireflyweb.aspx?prgname=login"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];
NSError *error = [[NSError alloc] init];
NSHTTPURLResponse *response = nil;
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSLog(@"Response code: %d", [response statusCode]);
if ([response statusCode] >=200 && [response statusCode] <300)
{
NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
NSLog(@"Response ==> %@", responseData);
SBJsonParser *jsonParser = [SBJsonParser new];
NSDictionary *jsonData = (NSDictionary *) [jsonParser objectWithString:responseData error:nil];
NSLog(@"%@",jsonData);
NSInteger success = [(NSNumber *) [jsonData objectForKey:@"success"] integerValue];
NSLog(@"%d",success);
if(success == 1)
{
NSLog(@"Login SUCCESS");
[self alertStatus:@"Logged in Successfully." :@"Login Success!"];
} else {
NSString *error_msg = (NSString *) [jsonData objectForKey:@"error_message"];
[self alertStatus:error_msg :@"Login Failed!"];
}
} else {
if (error) NSLog(@"Error: %@", error);
[self alertStatus:@"Connection Failed" :@"Login Failed!"];
}
}
}
@catch (NSException * e) {
NSLog(@"Exception: %@", e);
[self alertStatus:@"Login Failed." :@"Login Failed!"];
}
ログに JSON 応答がないことがわかるため、ログインが成功したかどうかはわかりません。この Web サイトにログインして、成功したかどうかに関係なく応答を得る他の方法はありますか?
ありがとう！