新しく作成された TVar を do ブロックで返すことは可能ですか? 私はこのコードを使用してこれを実装しようとしました:
type Buffer a = TVar [[(a,a)]]
newBuffer :: STM (Buffer a)
newBuffer = newTVar [[]]
launchGhosts :: [[(String,String)]] -> Buffer String
launchGhosts unblocked = do buff <- atomically newBuffer
atomically $ put buff unblocked
return buff
computeBlock :: Buffer String -> IO()
computeBlock buff = do i <- atomically $ get buff
putStrLn $ show i
put :: Buffer a -> [[(a,a)]] -> STM ()
put buff x = do writeTVar buff x
get :: Buffer a -> STM [[(a,a)]]
get buff = do x <- readTVar buff
return x
これにより、共有メモリを初期化し、プログラム内の別の場所で使用できるようになります。メモリの初期化を分離したい主な理由は、メモリを何度も初期化せずに並行関数を複数回呼び出すことです。
型チェッカーは、次の 2 つのエラーをスローします。
pacman.hs:65:29:
No instance for (Monad TVar)
arising from a do statement
Possible fix: add an instance declaration for (Monad TVar)
In a stmt of a 'do' block: buff <- atomically newBuffer
In the expression:
do { buff <- atomically newBuffer;
atomically $ put buff unblocked;
computeBlock buff;
return buff }
In an equation for `launchGhosts':
launchGhosts unblocked
= do { buff <- atomically newBuffer;
atomically $ put buff unblocked;
computeBlock buff;
.... }
pacman.hs:65:37:
Couldn't match expected type `TVar t0' with actual type `IO a0'
In the return type of a call of `atomically'
In a stmt of a 'do' block: buff <- atomically newBuffer
In the expression:
do { buff <- atomically newBuffer;
atomically $ put buff unblocked;
computeBlock buff;
return buff }
問題が何であるか、またはこのコードの背後にあるアイデアを実装する別の方法を知っている人はいますか?
アップデート:
launchGhosts :: [[(String,String)]] -> IO(Buffer String)
launchGhosts unblocked = do buff <- atomically newBuffer
atomically $ put buff unblocked
return buff
computeBlock :: IO(Buffer String) -> IO()
computeBlock buff = do i <- atomically $ get buff
putStrLn $ show i
アップデート:
pacman.hs:71:46:
Couldn't match expected type `Buffer a0'
with actual type `IO (Buffer String)'
In the first argument of `get', namely `buff'
In the second argument of `($)', namely `get buff'
In a stmt of a 'do' block: i <- atomically $ get buff