これは以前に質問されて回答されたか、誰かが適切に回答する前に質問が閉じられた可能性があります。誰かがそれをグーグルで検索した場合に備えて、ここに答えがあります:
https://developer.mozilla.org/en-US/docs/DOM/DOMParser
var parser = new DOMParser();
var doc = parser.parseFromString(stringContainingXMLSource, "application/xml");
// returns a Document, but not a SVGDocument nor a HTMLDocument
parser = new DOMParser();
doc = parser.parseFromString(stringContainingXMLSource, "image/svg+xml");
// returns a SVGDocument, which also is a Document.
parser = new DOMParser();
doc = parser.parseFromString(stringContainingHTMLSource, "text/html");
// returns a HTMLDocument, which also is a Document.
/*
* DOMParser HTML extension
* 2012-09-04
*
* By Eli Grey, http://eligrey.com
* Public domain.
* NO WARRANTY EXPRESSED OR IMPLIED. USE AT YOUR OWN RISK.
*/
/*! @source https://gist.github.com/1129031 */
/*global document, DOMParser*/
(function(DOMParser) {
"use strict";
var
DOMParser_proto = DOMParser.prototype
, real_parseFromString = DOMParser_proto.parseFromString
;
// Firefox/Opera/IE throw errors on unsupported types
try {
// WebKit returns null on unsupported types
if ((new DOMParser).parseFromString("", "text/html")) {
// text/html parsing is natively supported
return;
}
} catch (ex) {}
DOMParser_proto.parseFromString = function(markup, type) {
if (/^\s*text\/html\s*(?:;|$)/i.test(type)) {
var
doc = document.implementation.createHTMLDocument("")
;
doc.body.innerHTML = markup;
return doc;
} else {
return real_parseFromString.apply(this, arguments);
}
};
}(DOMParser));