php - MySQL の NULL 値を置き換える

Question

これを使用するときに空の行を見つけて置き換える方法.....

$Qemaster="select * from emaster where `branch`='$bid' and `department`='$did' and `status`!='L'";
$Remaster=mysql_query($Qemaster);
while($Rowemaster=mysql_fetch_array($Remaster)){
    $empcode=$Rowemaster[id];
    $name=$Rowemaster[name];
    $Tleave=0;

echo "<tr>";
echo "<td rowspan='2'>".$name."</td>";
echo "<td>Leave</td>";

$Qlp="select * from lpsummary where ((`month` IN(04,05,06,07,08,09,10,11,12) and `year`='$year') or (`month` IN (01,02,03) and `year`='$Nyear')) and `empcode`='$empcode'";
$Rlp=mysql_query($Qlp);
$RRlp=mysql_num_rows($Rlp);
while($Rowlp=mysql_fetch_array($Rlp)){  

$leave=$Rowlp['leave'];
$Tleave=$Tleave+$leave;
if($leave==NULL){
    $Eleave='-';
}
else{
    $Eleave=$leave;
}
echo "<td>".$Eleave."</td>";
}
echo "<td><font color='red'>".$Tleave."</font></td>";
echo "<td><font color='green'>".substr(($Tleave/$RRlp),0,4)."</font></td>";
echo "<tr><td>Percentage</td>";
}

空の行がある場合...私はそれを次のように置き換えたいです - 代わりに echo "".$Eleave."";