0

私は配列を持っています { $address = array(..........);} 私はそれを { のように変換しました

foreach ($address as $key => $val){
    $points[] = "['{$val}', '{$val}']";
}
$output = join ("," , $points);
$req_format = strip_tags($output);

}

['30 South Wacker Drive Floor 22 Chicago IL 60606 ', '30 South Wacker Drive Floor 22 Chicago IL 60606 '],['288 Bishopsgate London, EC2M 4QP United Kingdom ', '288 Bishopsgate London, EC2M 4QP United Kingdom '],['260 Madison Avenue 8th Floor New York NY 10016', '260 Madison Avenue 8th Floor New York NY 10016']

この値を js 変数に割り当てる必要があります。

var locationsArray = [
['30 South Wacker Drive Floor 22 Chicago IL 60606', '30 South Wacker Drive Floor 22 Chicago IL 60606'],
['30 South Wacker Drive Floor 22 Chicago IL 60606', '30 South Wacker Drive Floor 22 Chicago IL 60606']
];

php 変数 $req_format を js 変数 locationArray = [??????]; に割り当てるにはどうすればよいですか?

4

2 に答える 2

1

代わりに json を使用できます。

foreach ($address as $key => $val){
    $points[] = "['{$val}', '{$val}']";
}
$jsoned = json_encode($points);
//pass it to your js
var js_data = "<?php echo $jsoned; ?>";
于 2013-06-11T05:18:53.540 に答える
0
foreach ($address as $key => $val){
    $val = strip_tags($val);
    $points[] = array($val, $val);
}
$json = json_encode($points);
$json = str_replace('\n',' ',$json);
$json = str_replace('\r',' ',$json);

var locations = '<?php echo $json;?>';
var locations_array = JSON.parse(locations);

var locationsArray = locations_array;
于 2013-06-12T19:02:23.577 に答える